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Yuri [45]
3 years ago
10

The amount of grass seed needed to cover a lawn is proportional to its area. The lawn is rectangular and has an area of 2c^2 + 2

c square meters. Factor this polynomial to find possible expressions for the length and width of the lawn. (Assume the factors are polynomials.) HELP ASAP!!
Mathematics
1 answer:
natka813 [3]3 years ago
7 0
2c is a factor of both terms.
.. area = 2c(c+1)

Possible expressions for length and width are
  1, 2, c, 2c, c+1, 2(c+1), c(c+1), 2c(c+1).
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A lake initially contains 3000 fish. Suppose that in the absence of predators or other causes of removal, the fish population in
katrin [286]

Let x = number of months.

Let y = total number of fish in pond.

6% of 3,000 = 180 fish

We can use an equation to help us with this problem.

y = 3,000 + 180x - 400x. Combine like terms.

y = 3,000 - 220x. Plug 9 in for x.

y = 3,000 - 220(9). Solve for y

y = 1,020.

There are 1,020 fish in the pond after 9 months.

7 0
3 years ago
1) 6=A/4+2 can someone help please
monitta

Answer:

A=16

Step-by-step explanation:

6=A/4+2

-2       -2

4=A/4

x4  x4

16=A

6 0
2 years ago
7x - 3x = 24
Debora [2.8K]
7x - 3x = 24
The 7x and the 3x are both like terms, so they can be combined. 7 - 3 is 4, so the equation turns into
4x = 24
Now, you want to get the x alone, so you divide both sides by 4 because it is the opposite of multiplication. 24 divided by 4 is 6, so
x = 6
4 0
3 years ago
Read 2 more answers
PLS HELP!!! :(( need a good grade
Olegator [25]

Answer:

The closest answer I got was 29555.50.

Step-by-step explanation:

I used the rate r=0.0825/12 to represent the monthly rate and used that for the whole equation. I final answe I got by plugging in the numbers was 29555.11248. So I'm not too sure whether or not it't correct,

7 0
3 years ago
Read 2 more answers
What is the square root of 129
Juli2301 [7.4K]
If you are allowed to use a calculator then you only need to press the buttons. 

Assuming you cannot use a calculator you need to use approximation techniques. First let us begin by finding the two closest numbers that are perfect squares. In this case 11^2 and 12^2 are the closest square numbers to 129. 

11^2 = 121
12^2 = 144
We can already tell that the square root of 129 is closer to 11 than to 12. 
Now we need to get even closer.
If you try squaring a number like 11.5 then you can get even closer to 129. When you square 11.5 you get 132.25. Already you can tell that the square root of 129 is close to the square root of 132.25 or 11.5
Now we can get even closer square the number 11.25 and keep on going until one of these numbers when squared is almost or exactly 129. I hope I helped, there really isn't a great way to do this without a calculator, or by using the graph of y=x^2
7 0
2 years ago
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