Answer:
the measure of AB equals the measure of BC
2x+1=3x-4
4+1=3x-2x
5=x
BC=3x-4=3*5-4=15-4=11
AB=2x+1=2*5+1=10+1=11
AC=AB+BC=11+11=22
Step-by-step explanation:
For this case we have:
x: Represents the number of carrot boxes
y: Represents the number of boxes of potatoes
Initially we have:

If you sold 68 boxes of carrot we have:

If you sold 71 boxes of potatoes, we have:

The number of boxes I take home is given by:
ANswer:
7 boxes of carrots left
There are 9 boxes of potatoes left
A total of 16 boxes remain
Answer:
Step-by-step explanation:
We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.
Therefore we have the following raffle tickets:
123
132
213
231
312
321
000
000
From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.
Probability of 123 to be picked=
1/8 => 0.125
Probability of 000 to be picked=
2/8 => 0.25
Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked
Answer: 110°
<u>Step-by-step explanation:</u>
∠A ≅ ∠B
since ∠A = 35° (given), then ∠B = 35°
Use the Triangle Sum Theorem to find ∠C:
∠A + ∠B + ∠Q = 180°
35° + 35° + ∠Q = 180°
70° + ∠Q = 180°
∠Q = 110°
The central angle (∠AQB) ≅ arc AB
since ∠AQB = 110° (solved above), then arc AB = 110°
Answer:
18
Step-by-step explanation: