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AVprozaik [17]
3 years ago
14

Math Help Please will give brainliest! Dont answer if not sure.

Mathematics
1 answer:
leva [86]3 years ago
6 0
First you find the area of the square which is 8²=64 than you find the area of a circle using the formula πr² you get 201.06 and divide it by 4 because you only need the quarter and you get 50.26 the last step is to add the two areas together and you get 64+50.26=114.2
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Regular pentagonal tiles and triangular tiles are arranged in the pattern shown. The pentagonal tiles are all the same size and
professor190 [17]
First of all you have to find the missing measurements. The actual measurements for the angles in the hexagon are not given, but they give you an expression. You have to solve for x first so that you can plug it in and find the angle measurement. You have to equal the two sides that are given to you like this: 20x+48=33x+9. You solve for x and then plug it into each angle measurement. This should give you 108. Since it is a regular hexagon all of the sides are equal. If you look at the angle at the top of the hexagon you'll see two triangles and the angle. Since it lies on a straight line, it is all equal to 180. You already have the angle measurement of the hexagon and are missing the triangles. So 180-108=72. 72 is the missing part of the angle. You divide this by 2 in order to find each triangle angle measurements. the answer is 36 degrees. 
7 0
3 years ago
Explain how you know that the values of the digit 5 in numbers 150,000 and 100,500 are not the same.
bagirrra123 [75]
The digit 5 in the number 150,000 represents 50,000 (fifty thousands) while the digit 5 in 100,500 represents 500 (five hundreds).
3 0
4 years ago
Read 2 more answers
What is the difference between 63 degree fahrenheit and negative 16 degrees fahrenheit
professor190 [17]
It is 63-(-16) or 63+16 which is 79. So the difference is 79 degrees Fahrenheit
8 0
3 years ago
Read 2 more answers
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

4 0
4 years ago
HELP ASAP 5/6b- 3/4=6
zimovet [89]

Answer:

b= 8 1/10 i think

Step-by-step explanation:

you might want to test it out tho. I really hope this helps

6 0
3 years ago
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