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Dafna11 [192]
3 years ago
6

A hyperbola with center at (0, 0), with x-intercepts at (4, 0) and (-4, 0), with b = 1, and opening horizontally has the equatio

n

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
5 0
For a hyperbola, the traverse axis, where it opens at, in this case horizontally or the x-axis, is the one that has the positive fraction, in this case then, it will be the fraction with the "x" variable in it.

check the picture below, you can pretty much see from the x-intercepts, what the vertices are, and thus what "a" is.

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Read 2 more answers
Write an equation in point slope form for the line that passes through (-5,6) and (-3,-9).
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\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{6})\qquad
(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-9})
\\\\\\
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\bf \begin{array}{|c|ll}
\cline{1-1}
\textit{point-slope form}\\
\cline{1-1}
\\
y-y_1=m(x-x_1)
\\\\
\cline{1-1}
\end{array}\implies y-6=-\cfrac{15}{2}[x-(-5)]\implies y-6=-\cfrac{15}{2}(x+5)
\\\\\\
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