A hyperbola with center at (0, 0), with x-intercepts at (4, 0) and (-4, 0), with b = 1, and opening horizontally has the equatio
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1 answer:
For a hyperbola, the traverse axis, where it opens at, in this case horizontally or the x-axis, is the one that has the positive fraction, in this case then, it will be the fraction with the "x" variable in it.
check the picture below, you can pretty much see from the x-intercepts, what the vertices are, and thus what "a" is.
check the picture below, you can pretty much see from the x-intercepts, what the vertices are, and thus what "a" is.
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The Law of Cosines is used for this purpose.
c² = a² + b² - 2ab·cos(C)
c² = 5² + 4² - 2·5·4·cos(60°)
c² = 25 + 16 - 20 = 21
c = √21
The length of side c is √21 ≈ 4.583.
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If you really intend the side lengths to be 55 and 44, your result is c≈50.408, the above value times 11.
c² = a² + b² - 2ab·cos(C)
c² = 5² + 4² - 2·5·4·cos(60°)
c² = 25 + 16 - 20 = 21
c = √21
The length of side c is √21 ≈ 4.583.
_____
If you really intend the side lengths to be 55 and 44, your result is c≈50.408, the above value times 11.