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3 years ago

Α-(α-90°)=(α-180°)-α Pls help!

1 answer:

6 0

90=(a-180)-a 90=-180 That result is not possible so the answer should be undefined. If I am wrong and there is a solution, you can find it by Google searching a graphing calculator and then put the two equations y=x-(x-90) and y=(x-180)-x into the calculator. The x value for where the two equations intersect is the a value you are looking for. If the graphs never intersect, there is no solution like what my work shows. I hope this helps.

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In figure if AB is parrallel to CD,

lara31 [8.8K]

Answer:

Yes

Step-by-step explanation:

They are parallel lines basically, ingnore the measurements and the traingle, they were put there to confuse you.

Hope this helps

Never30

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3 years ago

United Flight 15 from New York's JFK airport to San Francisco uses a Boeing 757-200 with 182 seats. Because some people with res

Tcecarenko [31]

Answer:

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

Step-by-step explanation:

For each passenger, there are only two outcomes possible. Either they show up for the flight, or they do not show up. This means that we can solve this problem using binomial distribution probability concepts.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A probability is said to be unusually low if it is lower than 5%.

For this problem, we have that:

There are 200 reservations, so $n = 200$ .

A passenger consists in a passenger not showing up. There is a .0995 probability that a passenger with a reservation will not show up for the flight. So $\pi = 0.0995$ .

Find the probability that when 200 reservations are accepted for United Flight 15, there are more passengers showing up than there are seats available.

X is the number of passengers that do not show up. It needs to be at least 18 for the flight not being overbooked. So we want to find $P(X < 18)$ , with $\pi = 0.0995, n = 200$ . We can use a binomial probability calculator, and we find that:

$P(X < 18) = 0.2927$ .

There is a 29.27% probability that the flight is overbooked. This is not an unusually low probability. So it does seem too high so that changes must be made to make it lower.

5 0

2 years ago

Which technique is most appropriate to use to solve each equation? Drag the name of the technique into the box to match each equ

NemiM [27]

For the first equation, the answer is C) completing the square.
For the second equation, the answer is B) zero product property.

For the first equation, we can easily complete the square by finding half of b and squaring it; then we can take the square root of both sides and solve the equation.

For the second equation, since it is already factored, we use the zero product property to solve it.

7 0

3 years ago

In the year 2002, the world population was estimated at 6 billion people. Based on research from the World Bank, about 20% lived

olga_2 [115]

In the given question all the information's are provided based on which the answer to the question can be easily deduced. It is already given that the population of the world in the year 2002 was estimated to about 6 billion. Among them 20% of the people lived on an an income of less that $1 per day.Firstly let us convert 6 billion from words to numbers.
6 billion = 6000000000
Now
Number of people earning less that $1 per day = (20/100) * 6000000000
= 6000000000/5
= 1200000000
So the number of people earning less than $1 per day is 1200000000

8 0

2 years ago

The average height of boys at Greg's school is 5'9" with a

ipn [44]

1- almost 100
2- 83.85

3 0

2 years ago