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4 years ago

Α-(α-90°)=(α-180°)-α Pls help!

1 answer:

6 0

90=(a-180)-a 90=-180 That result is not possible so the answer should be undefined. If I am wrong and there is a solution, you can find it by Google searching a graphing calculator and then put the two equations y=x-(x-90) and y=(x-180)-x into the calculator. The x value for where the two equations intersect is the a value you are looking for. If the graphs never intersect, there is no solution like what my work shows. I hope this helps.

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Find the missing angle measures by examining the angle relationships first m m m

Katyanochek1 [597]

∠ b = 43° — — { Vertical opp. angles]

Now, see 43 and a are together compromising the linear pair so,

= 43 + a = 180°

= a = 180 - 43

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3 years ago

What is the awnser for this question?

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Answer:

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Step-by-step explanation:

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3 years ago

Marilyn knows that she needs $45,000 for a down payment on a house. She found an investment that earns 3.15% interest compoundin

laila [671]

She should save $38,450.39.

The formula for the amount of money in an interest-bearing account that is compounded is

$A=p(1+\frac{r}{n})^{nt}$

where A is the total amount in the account, p is the amount of principal invested, r is the interest rate as a decimal number, n is the number of times per year interest is compounded, and t is the number of years. Using our information we have:

$45000=p(1+\frac{0.0315}{12})^{12\times5}
\\
\\45000=p(1.002625)^{60}$

Divide both sides:
$\frac{45000}{1.002625^{60}}=\frac{p(1.002625)^{60}}{1.002625^{60}}
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3 years ago

| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the

Westkost [7]

Answer:

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

Left Speed(km/h) Time

Car: 12PM X

Van: 12PM 60

Car/Van

DistanceCar AB + z

DistanceVan Az

Ratio: (AB+z)/Az = 7/5

Time until both meet = T (in hours)

Distance Car: xT

Distance Van: 60T

====

xT = AB + z

60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is: time (hr) = 108 km/(84 km/h)

time = 1.286 hours

Distance for at 1.289 hours is: distance (km) = (60 km/h)*(1.286 h)

distance = 77.14 km

At 1.286 hours, the car reverses direction. The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours. The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let t be the time after 1.286 hours that both vehicles meet/collide.

t*(60 km/h) + t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a) Time until both vehicles meet is 1.5 hours after starting at noon. That makes it 1:30PM.

b) Average speed of car is 84 km/h

==============

CHECK

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

YES

3 0

2 years ago

Consider the isosceles triangle with verticles a(-1,1) b(3,1) c(1,6)

Dima020 [189]

What is the question? Do they want us to find a’,b’, and c’??

8 0

4 years ago