X=number of books that cost 0.60
y=number of books that cost 0.75
x+y=16
0.6x+0.75y=10.95
solve
multiply second equation by 10 for nicity
6x+7.5y=109.5
multiply first equesiotn by -6 and add to second
-6x-6y=-96
<u>6x+7.5y=109.5 +</u>
0x+1.5y=13.5
1.5y=13.5
divide both sides by 1.5
y=9
sub back
x+y=16
x+9=16
minus 6
x=7
seven 0.60 books and nine 0.75 books
Answer:
C
Step-by-step explanation:
If you plug in the numbers into that equation you get
1 = -2(2) + 5
1 = -4 + 5
1 = 1
You can also do this again with x = 5 y = -5
-5 = -2(5) + 5
-5 = -10 + 5
-5 = -5
The number is 28.
The equation would be:
237 + 6(x) = 405
The problem states that 6 times the opposite of a number, however, since the number sign was not given, we do not know whether it is in a positive or negative form. So we leave it as only x.
237 + 6x = 405
6x = 405 - 237
6x = 168
6x / 6 = 168 / 6
x = 28
To check:
237 + 6 (28) = 405
237 + 168 = 405
405 = 405
Answer:
(7w + 9x)(7w - 9x)
Step-by-step explanation:
Given expression;
49w² - 81x²
Now to solve the problem;
49w² - 81x² = 7²w² - 9²x²
Using differences of two squares;
x² - y² = (x + y)(x - y)
So;
7²w² - 9²x² = (7w + 9x)(7w - 9x)
Answer:
<h2>The answer is 0.23(approx).</h2>
Step-by-step explanation:
The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.
We need to find the probability of getting exactly 3s as the result.
From the sequence of 6 independent rolls, 2 rolls can be chosen in 
ways.
The probability of getting two 3 as outcome is 
.
In the rest of the 4 sequences, will not be any 3 as outcome.
Probability of not getting a outcome rather than 3 is 
.
Hence, the required probability is 
≅0.2966 or, 0.23.
