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Mademuasel [1]
3 years ago
12

Ming made a triangular picture frame out of cardboard. The sides of the frame are 6.75 in., 6.75 in., and 8.375 in. Ming uses th

e addition below to determine the amount of string she needs to decorate the edges of the frame.
Which explains Ming’s error?

A. She should have included the decimal in 6.75 and aligned the decimal points to add 6.750 + 6.750 + 8.375 = 21.875.
B. She forgot to put the decimal point in two of the numbers: 0.675 + 0.675 + 8.375 = 9.725..
C. She added 6.75 twice, and she should have only added it once: 6.75 + 8.375 = 15.125.
D. She should have placed a zero placeholder after the decimal point to add 6.075 + 6.075 + 8.375 = 20.525.

Mathematics
2 answers:
netineya [11]3 years ago
8 0

Answer:

A hope this helps

Step-by-step explanation:

bija089 [108]3 years ago
4 0
The answer is A. When adding decimals, you need to line up the decimal points before adding them together. To make the problems clear, adding zeroes at the end of the numbers will help make the alignment clear.

   6.750
   6.750
<u>+ 8.375</u>
<u /> 21.875
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Answer: (B)
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But a more intuitive way is to determine what happens during each transformation.
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6 0
4 years ago
Read 2 more answers
five consecutive terms of an arithmetic sequence have a sum of 40. The product of the middle and the two end terms is 224. Find
ratelena [41]
Let the five terms be: a, a + d, a + 2d, a + 3d, a + 4d, then
a + a + d + a + 2d + a + 3d + a + 4d = 5a + 15d = 40
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Also, (a + 2d)(a + 3d)(a + 4d) = 224
(a + 3d - d)(a + 3d)(a + 3d + d) = 224
(8 - d)(8)(8 + d) = 224
(8 - d)(8 + d) = 224/8 = 28
64 - d^2 = 28
d^2 = 64 - 28 = 36
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Therefore, the term of the sequence is: -10, -10 + 6, -10 + 2(6), -10 + 3(6), -10 + 4(6)
= -10, -4, -10 + 12, -10 + 18, -10 + 24
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4 0
3 years ago
Any help would be appreciated(brainly for best answer)
svp [43]

Answer:

i believe it is the answer on the right because alternate interior angles add up to 180 degrees

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JulijaS [17]
If you're just asking for how that'd look in algebraic form then the answer would be v+50/2
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