The rectangels the first one and the one belo it
1 1/12 i’m pretty sure is the answer
The question is incomplete. Here is the complete question.
m∠J and m∠Kare base angles of an isosceles trapezoid JKLM.
If m∠J = 18x + 8, and m∠M = 11x + 15 , find m∠K.
A. 1
B. 154
C. 77
D. 26
Answer: B. m∠K = 154
Step-by-step explanation: <u>Isosceles</u> <u>trapezoid</u> is a parallelogram with two parallel sides, called Base, and two non-parallel sides that have the same measure.
Related to internal angles, angles of the base are equal and opposite angles are supplementary.
In trapezoid JKLM, m∠J and m∠M are base angles, so they are equal:
18x + 8 = 11x + 15
7x = 7
x = 1
Now, m∠K is opposite so, they are supplementary, which means their sum results in 180°:
m∠J = 18(1) + 8
m∠J = 26
m∠K + m∠J = 180
m∠K + 26 = 180
m∠K = 154
The angle m∠K is 154°
Answer:
5√3 = b
5 = d
10√3 = a
15 = c
Step-by-step explanation:
Sin60° = opp/hyp
sin60° = b/10
10sin60° = b
5√3 = b
Cos60° = adj/hyp
Cos60° = d/10
10Cos60° = d
5 = d
Sin30° = opp/hyp
Sin30° = 5√3/a
a = 5√3/Sin30°
a = 10√3
Tan30° = opp/adj
Tan30° = 5√3/c
c = 5√3/tan30°
c = 15
