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Burka [1]
3 years ago
14

The length of a rectangle picture frame is 2 centimeters more than twice it’s width. If the area of the frame is 364 square cent

imeters, find the length and width of the frame

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

Length:28 cm

Width: 13 cm

Step-by-step explanation:

Let

x ---> the length of a rectangle picture frame

y ---> the width of a rectangle picture frame

we know that

The area of a rectangle picture frame is equal to

A=xy

we have

A=364\ cm^2

so

364=xy ----> equation A

The length of a rectangle picture frame is 2 centimeters more than twice it’s width

so

x=2y+2 ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (28,13)

see the attached figure

therefore

Length:28 cm

Width: 13 cm

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inna [77]

Answer:

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Step-by-step explanation:

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3 years ago
Describe the transformation of the graph of f into the graph of g as either a horizontal or vertical stretch. f(x)=sqrt(x) and g
SpyIntel [72]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{  B}}\textit{ is negative}\\
\left. \qquad   \right.  \textit{reflection over the y-axis}

\bf \bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
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with that template in mind, let's see    \bf f(x)=\sqrt{x}\qquad 
\begin{array}{llll}
g(x)=&\sqrt{0.5x}\\
&\quad \uparrow \\
&\quad  B
\end{array}

so B went form 1 on f(x), down to 0.5 or 1/2 on g(x)
B = 1/2, thus the graph is stretched by twice as much.
8 0
3 years ago
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alexandr1967 [171]

Answer:

Step-by-step explanation:

4x + 3y = -1         --------------(i)

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multiply equation (i) by 3

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Answer:

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Good luck!

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From Uzbekistan.

6 0
3 years ago
Ok i have a few questions please give examples and descriptions as well
Arte-miy333 [17]

Answer:

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2)Where you multiply the two exponents together

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Step-by-step explanation:

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