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Burka [1]
3 years ago
14

The length of a rectangle picture frame is 2 centimeters more than twice it’s width. If the area of the frame is 364 square cent

imeters, find the length and width of the frame

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

Length:28 cm

Width: 13 cm

Step-by-step explanation:

Let

x ---> the length of a rectangle picture frame

y ---> the width of a rectangle picture frame

we know that

The area of a rectangle picture frame is equal to

A=xy

we have

A=364\ cm^2

so

364=xy ----> equation A

The length of a rectangle picture frame is 2 centimeters more than twice it’s width

so

x=2y+2 ---> equation B

Solve the system by graphing

Remember that the solution is the intersection point both graphs

The solution is the point (28,13)

see the attached figure

therefore

Length:28 cm

Width: 13 cm

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29. The table below represents the relationship of the price of carrots to their weight in ounces in a market: Price Weight, in
Alinara [238K]

The proportional relationship that represents the market that sells their carrots at a lower rate per pound is: y = 1.6x.

<h3>What is a proportional relationship?</h3>

A proportional relationship is a function in which the output variable is given by the input variable multiplied by a constant of proportionality, that is:

y = kx

In which k is the constant of proportionality.

From the table, the rate is:

k = $8.8/4.4 = 2.

From the market, the rate is:

k = $4.8/3 = $1.6.

Hence the equation is y = 1.6x.

More can be learned about proportional relationships at brainly.com/question/10424180

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3 0
2 years ago
The rate of change of revenue (in dollars per calculator) from the sale of x calculators is R′(x)=(x+1)ln(x+1)R ′ (x)=(x+1)ln(x+
jekas [21]

Answer:

Total revenue = \frac{169}{2}\ln(13)-\frac{169}{4}  dollars

Step-by-step explanation:

R'(x)=(x+1)\ln(x+1)

Integrate with respect to x.

R(x)= ∫(x+1)\ln(x+1) dx

Take x+1=u

Differentiate with respect to x

dx=du

So,

R(x)= ∫u\ln(u)\,du

Use integration by parts: ∫f g dx = f∫ g dx-∫(∫g dx)f' dx

Therefore,

R(x)=  \frac{u^2}{2}\ln(u) -  ∫\frac{u^2}{2}\frac{1}{u}\,du

=  \frac{u^2}{2}\ln(u) -  ∫\frac{u}{2}\,du

Put u=x+1

R(x)=   \frac{(x+1)^2}{2}\ln(x+1)-\frac{(x+1)^2}{4}

To find total revenue from the sale of the first 12 calculators, put x=12

R(x)=   \frac{(12+1)^2}{2}\ln(12+1)-\frac{(12+1)^2}{4}\\\\= \frac{(13)^2}{2}\ln(13)-\frac{(13)^2}{4}\\\\=\frac{169}{2}\ln(13)-\frac{169}{4}

Total revenue = \frac{169}{2}\ln(13)-\frac{169}{4}  dollars

4 0
3 years ago
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