Question

There are 9 red and 6 green marbles in a bag. A child reaches in the bag and randomly takes one marble. What is the probability pf that child getting a green marble

Answer 1

Answer:  The required probability that the child took a green marble is 40%.

Step-by-step explanation:  Given that there are 9 red and 6 green marbles in a bag and a child reaches in the bag and randomly takes one marble.

We are to find the probability that the child took a green marble.

Let S denote the sample space of choosing a marble from the bag and A be the event of choosing a green marble.

Then,

n(S) = 9 + 6 = 15   and   n(A) = 6.

Therefore, the probability of event A will be

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{6}{15}=\dfrac{2}{5}\times 100\%=40\%.$

Thus, the required probability that the child took a green marble is 40%.

Answer 2

 2/5
The probability is the green over the total