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kolezko [41]
3 years ago
9

You're playing a game where you defend your village from an orc invasion. There are 3 characters (elf, hobbit, or human) and 5 d

efense tools (magic, sword, shield, slingshot, or umbrella) to pick from. If you randomly choose your character and tool, what is the probability that you'll be a magic elf?
Mathematics
2 answers:
Kruka [31]3 years ago
8 0

Answer:

it is 1/15

Step-by-step explanation:

Salsk061 [2.6K]3 years ago
5 0

Answer:

1/15

Step-by-step explanation:

You have a 1/3 chance of being an elf.

You have a 1/5 change of having the magic tool.

1/3 × 1/5 = 1×1/3×5 = 1/15

You might be interested in
1. Find the product. Simplify. 13/14 of 10/9. A. 15/42 B. 5/21 C. 2/7 D. 5/6 2. Andy has 5 pots, and each pot can hold 3/8 pound
Rufina [12.5K]

1) Resultant fraction: \frac{65}{63}

2) Total soil: 1\frac{7}{8} pounds

3) Result of the product: \frac{35}{2}

Step-by-step explanation:

1)

In this problem, we want to find the product between the two fractions

\frac{13}{14}

and

\frac{10}{9}

In order to find this product, we have to multiply the numerators of each fraction and the denominators of each fraction. We get:

\frac{13}{14}\cdot \frac{10}{9}=\frac{13\cdot 10}{14\cdot 9}=\frac{130}{126}

Now we simplify, dividing both numerator and denominator by 2:

\frac{130/2}{126/2}=\frac{65}{63}

And the fraction cannot be further simplified.

2)

Here we have:

n = 5 (number of pots that Andy has)

s=\frac{3}{8} (amount of soil (in pounds) that each pot can contain)

In order to find the amount of soil that Andy needs to fill all the pots, we have to multiply the number of pots (n) by the amount of soil that each pot can contain (s).

If we do so, we find:

t=n \cdot s = 5 \cdot \frac{3}{8}=\frac{5\cdot 3}{8}=\frac{15}{8}

Which can be rewritten as a mixed fraction as:

\frac{15}{8}=\frac{8+7}{8}=\frac{8}{8}+\frac{7}{8}=1\frac{7}{8}

3)

Here we want to find the result of the following product:

4\frac{2}{3}\cdot 3\frac{3}{4}

In order to do so, we first have to rewrite each fraction as an improper fraction.

For the 1st fraction:

4\frac{2}{3}=\frac{4\cdot 3+2}{3}=\frac{12+2}{3}=\frac{14}{3}

For the 2nd fraction:

3\frac{3}{4}=\frac{3\cdot 4+3}{4}=\frac{12+3}{4}=\frac{15}{4}

Now we can finally find the product of the two fractions:

\frac{14}{3}\cdot \frac{15}{4}=\frac{14\cdot 15}{3\cdot 4}=\frac{210}{12}=\frac{35}{2}

Where in the last step, we divide both the numerator and the denominator by 6.

Learn more about fractions:

brainly.com/question/605571

brainly.com/question/1312102

#LearnwithBrainly

6 0
3 years ago
Which equation can you use to solve for x?
avanturin [10]
Opposite angles are equal so the equation is 

x + 71 = 108   (A)
3 0
3 years ago
Read 2 more answers
Sady students took a math test. The percentages of students who scored an A, B, C, or D are displayed in the circle graph,
valina [46]
Bob the builder was happy with this
8 0
3 years ago
the scale of a map is 1 in :250 miles City A is 378 miles from City B To the nearest tenth how far is its distance on the map
avanturin [10]
1.5 inches. You take 378 and divide it by 250
3 0
3 years ago
Which of the following are true statements about angle parking. Angle parking spots have a larger blind spaces than perpendicula
S_A_V [24]

Answer:

Angle parking is more common than perpendicular parking.

Angle parking spots have half the blind spot as compared to perpendicular parking spaces

Step-by-step explanation:

Considering the available options, the true statement about angle parking is that" Angle parking is more common than perpendicular parking." Angle parking is mostly constructed and used for public parking. It is mostly used where the parking lots are quite busy such as motels or public garages.

Therefore, in this case, the answer is that "Angle parking is more common than perpendicular parking."

Also, "Angle parking spots have half the blind spot as compared to perpendicular parking spaces."

5 0
3 years ago
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