Question

What is the sum of zeros of the function y=6x^2-x-2 ?

Answer 1

$y=6x^2-x-2\ \ \ \Rightarrow\ \ \ \Delta=(-1)^2-4\cdot6\cdot(-2)=1+48=49\\\\\Delta>0\ \ \ \Rightarrow\ \ \ exist\ two\ zeros\ of\ the\ function\\\\Vieta's\ formulas:\ \ \ x_1+x_2=- \frac{b}{a} \\\\x_1+x_2=- \frac{-1}{6} = \frac{1}{6}\\\\Ans.\ \ \ The\ sum\ of\ zeros\ is\ \frac{1}{6}$

Answer 2

It factors out to (2x+1)(3x-2)
zeroes are -1/2 and 2/3 sum is 1/6
Final answer:
1/6