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3 years ago

How to make 24 with numbers 3,3,7,4

Mathematics

1 answer:

ASHA 777 [7]3 years ago

8 0

Answer:

3*(4-3+7) = 24

Step-by-step explanation:

(4-3+7) = 8

8*3 = 24

You're welcome :)

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In algebra a word that means something has been added

Crazy boy [7]

Answer:

Addition

Step-by-step explanation:

means to add

6 0

3 years ago

Read 2 more answers

Which is greater 8.016 or 8.16

shusha [124]

8.16 because .016 is not as close to a whole as .16

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3 years ago

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Ali, Carrie and Bryan received a sum of money. Bryan's money was 3/5 as much as Ali's money. The ratio of Ali's money to Carrie'

monitta

Answer:

The sum of money received by Ali, Carrie and Bryan is $ 740.

Step-by-step explanation:

At first we translate mathematically each sentence:

(i) Ali, Carrie and Bryan received a sum of money.

$a$ - Ali's money.

$b$ - Bryan's money.

$c$ - Carrie's money.

(ii) Bryan's money was $\frac{3}{5}$ of Ali's money.

$b = \frac{3}{5}\cdot a$ (1)

(iii) The ratio of Ali's money to Carrie's money was 4 : 1.

$\frac{a}{c} = 4$ (2)

(iv) Ali had $ 160 more than Bryan.

$a = b + 160$ (3)

After some algebraic handling, we have the following system of linear equations:

$3\cdot a - 5 \cdot b = 0$ (1b)

$a - 4\cdot c = 0$ (2b)

$a - b = 160$ (3b)

The solution of the system is: $a = 400$ , $b = 240$ , $c = 100$

The sum of money is:

$s = a + b + c$

$s = 740$

The sum of money received by Ali, Carrie and Bryan is $ 740.

4 0

3 years ago

A number cube is rolled three times. An outcome is represented by a string of the sort OEE (meaning an odd number on the first r

Kryger [21]

The probability of occurrence for the events A, B and C is; 1/4.

<h3>What is the probability of occurrence of.the described events?</h3>

For the first event A in which case, there's no odd number on the first two rolls, the possible events are; EEE and EEO. Consequently, the required probability is;

Event A = 2/8 = 1/4.

For the event B in which case, there's an even number on both the first and last rolls; the possible events are; EEE and EOE. Consequently, the required probability is;

Event B = 2/8 = 1/4.

For the event C in which case, there's an odd number on each of the first two rolls; the possible events are; OOO and OOE. Consequently, the required probability is;

Event C = 2/8 = 1/4.