The equation of the circle whose center is at (3, 7) and whose radius is 6 is a. (x + 3)² + (y + 7)² = 6 b. (x + 3)² + (y + 7)²

= 36 c. (x - 3)² + (y - 7)² = 36

Mathematics

1 answer:

kicyunya [14]3 years ago

8 0

$\bf \textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{7}{ k})\qquad \qquad 
radius=\stackrel{6}{ r}
\\\\\\
(x-3)^2+(y-7)^2=6^2\implies (x-3)^2+(y-7)^2=36$

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