3 years ago

HELP PLEASE! URGENT!

Mathematics

1 answer:

finlep [7]3 years ago

8 0

Answer:

$\boxed{B. \: 5 {x}^{6} + 5 {x}^{5} + 8 {x}^{2} - x + 2}$

Step-by-step explanation:

$= > (2 {x}^{6} + 8 {x}^{2} - x + 1) + (3 {x}^{6} + 5 {x}^{5} + 1) \\ \\ = > 2 {x}^{6} + 8 {x}^{2} - x + 1 + 3 {x}^{6} + 5 {x}^{5} + 1 \\ \\ = > 2 {x}^{6} + 3 {x}^{6} + 5 {x}^{5} + 8 {x}^{2} - x + 1 + 1 \\ \\ = > 5 {x}^{6} + 5 {x}^{5} + 8 {x}^{2} - x + 2$

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What is the 6th term of the geometric sequence where a1 = 1,024 and a4 = −16? 1 −0.25 −1 0.25

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The n-th term is given by

$a_n=a_1\cdot r^{(n-1)}\qquad\text{where r is the common ratio}$

Then we can find the common ratio from the given terms.

$\dfrac{a_4}{a_1}=\dfrac{a_1\cdot r^{(4-1)}}{a_1}=r^3=\dfrac{-16}{1024}=\left(\dfrac{-1}{4}\right)^3\\\\r=\dfrac{-1}{4}\\\\a_6=1024\left(\dfrac{-1}{4}\right)^5=-1$