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mr Goodwill [35]
3 years ago
10

HELP PLEASE! URGENT!

Mathematics
1 answer:
finlep [7]3 years ago
8 0

Answer:

\boxed{B. \: 5 {x}^{6}  + 5 {x}^{5}  + 8 {x}^{2}  - x + 2}

Step-by-step explanation:

=  > (2 {x}^{6}  + 8 {x}^{2} - x + 1) + (3 {x}^{6} + 5 {x}^{5}  + 1) \\  \\  =  > 2 {x}^{6}  + 8 {x}^{2} - x + 1 + 3 {x}^{6} + 5 {x}^{5}  + 1 \\  \\  =  > 2 {x}^{6}  + 3 {x}^{6}  + 5 {x}^{5}  + 8 {x}^{2}  - x + 1 + 1 \\  \\  =  > 5 {x}^{6}  + 5 {x}^{5}  + 8 {x}^{2}  - x + 2

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At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed st
EastWind [94]

<u>Answer:</u>

C. Left-handed: 48, Right-handed: 504

D. Left-handed: 30, Right-handed: 315

<u>Step-by-step explanation:</u>

We are given that there are 58 left-handed students and 609 right-handed students at East Middle School and these numbers of students are proportional to the number of left and right handed students at East Middle School.

Given the above information, we are are to determine which two options could be the the numbers of left-handed and right-handed students at West Junior High.

Ratio of right handed to left handed students at East Middle School = \frac{609}{58} = 10.5

Checking for ratios of the given options:

A. \frac{483}{42} =11.5

B. \frac{378}{28} =13.5

C. \frac{504}{48} =10.5

D. \frac{560}{56} =10

E. \frac{315}{30} =10.5

Therefore, the possible numbers of left-handed and right-handed students at West Junior High could be C. Left-handed: 48, Right-handed: 504 and D. Left-handed: 30, Right-handed: 315.

7 0
3 years ago
Read 2 more answers
A teacher is giving her students a lesson on inequalities and asks the class to suggest points that are included in the solution
Slav-nsk [51]
Neither of the students are correct
8 0
3 years ago
Mary buys a reel of thread for sewing. There are 10 m of thread on the reel. She uses 210 cm. How much is left on the reel in ce
galben [10]
10meters=1000cm
1000-210=890
Mary has 890 centimeters of thread left on the reel.
5 0
3 years ago
Expand the given power using the Binomial Theorem. (10k – m)5
agasfer [191]

Answer:

(10k - m)^{5}=100000k-50000k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

Step-by-step explanation:

* Lets explain how to solve the problem

- The rule of expand the binomial is:

(a+b)^{n}=(a)^{n}+nC1(a)^{n-1}(b)+nC2(a)^{n-2}(b)^{2}+nC3(a)^{n-3}(b)^{3}+...............+(b)^{5}

∵ The binomial is (10k-m)^{5}

∴ a = 10k , b = -m and n = 5

∴ (10k-m)^{5}=(10k)^{5}+5C1(10k)^{4}(-m)+5C2(10k)^{3}(-m)^{2}+5C3(10k)^{2}(-m)^{3}+5C4(10k)^{1} (-m)^{4}+5C5(10k)^{0}(-m)^{5}

∵ 5C1 = 5

∵ 5C2 = 10

∵ 5C3 = 10

∵ 5C4 = 5

∵ 5C5 = 1

∴ (10k-m)^{5}=100000k^{5}+(5)(10000)k^{4}(-m)+(10)(1000)k^{3}(m^{2})+(10)(100)k^{2}(-m^{3})+5(10k)^{1} (m^{4})+(10k)^{0}(-m^{5})

∴ (10k-m)^{5}=100000k^{5}-50000)k^{4}m+10000k^{3}m^{2}-1000k^{2}m^{3}+50km^{4}-m^{5}

5 0
3 years ago
Haruka hiked several kilometers in the morning. She hiked only
Alex_Xolod [135]

Answer:

14 km

Step-by-step explanation:

6 = M - .25M = .75M

M = 6/.75 =  8 km  in the  morning  

8 + 6 = 14

6 0
2 years ago
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