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3 years ago

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Jason and doug compute in the long jump at a track meet. jason's long jump was 98 inches. doug's long jump was 3 yards. how much

longer was doug's jump than jason's jump

1 answer:

Setler79 [48]3 years ago

3 0

Doug's jump was 10 inches longer than jason's jump <span>

</span>

<span>Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more</span>

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Solve for x: 4/5x + 4/3 = 2x

Drupady [299]

The answer is x=10/9

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3 years ago

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Rewrite the equation B - 7,536 = 2t as a function of t.

pav-90 [236]

Answer:

B = 2t + 7,536

Step-by-step explanation:

B - 7,536 = 2t

Add 7,536 to both sides.

B = 2t + 7,536

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3 years ago

Find the value of x in the given right triangle

olchik [2.2K]

Answer:

The answer to your question is x = 35°

Step-by-step explanation:

Data

angle x = ?

Opposite side = 7

Adjacent side = 10

Process

To answer this question use trigonometric functions. The trigonometric function that relates the Opposite side and the adjacent side is the tangent.

Tan x = Opposite side / Adjacent side

- Substitution

Tan x = 7 / 10

- Simplification

Tan x = 0.7

- Result

Tan⁻¹ x = x = 34.99 or x ≈ 35°

3 0

3 years ago

evelyn has $638.54 in her checking account. she must maintain a $500 balance to avoid a fee. she wrote a check for $159.50 today

Pachacha [2.7K]

The inequality is:

x + $488.04 ≥ $500

And the solution is

x ≥ $11.96

<h3>How to write and solve the inequality?</h3>

First, let's define x as the amount that she needs to deposit.

Now, we know that at the moment Evely has $638.54 in her bank account. Then she pays for $638.54, then she writes a check for $159.50, then we need to subtract that:

$638.54 - $159.50 = $488.04

Now she needs to deposit an amount x, such that her balance is at least $500, then we can write the inequality:

x + $488.04 ≥ $500

Solving that for x, we get:

x ≥ $500 - $488.04 = $11.96

She needs to deposit at least $11.96.

If you want to learn more about inequalities:

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4 0

1 year ago

Given $m\geq 2$, denote by $b^{-1}$ the inverse of $b\pmod{m}$. That is, $b^{-1}$ is the residue for which $bb^{-1}\equiv 1\pmod

goblinko [34]

$(2+3)^{-1}\equiv5^{-1}\pmod7$ is the number <em>L</em> such that

$5L\equiv1\pmod7$

Consider the first 7 multiples of 5:

5, 10, 15, 20, 25, 30, 35

Taken mod 7, these are equivalent to

5, 3, 1, 6, 4, 2, 0

This tells us that 3 is the inverse of 5 mod 7, so <em>L</em> = 3.

Similarly, compute the inverses modulo 7 of 2 and 3:

$2a\equiv1\pmod7\implies a\equiv4\pmod7$

since 2*4 = 8, whose residue is 1 mod 7;

$3b\equiv1\pmod7\implies b\equiv5\pmod7$

which we got for free by finding the inverse of 5 earlier. So

$2^{-1}+3^{-1}\equiv4+5\equiv9\equiv2\pmod7$

and so <em>R</em> = 2.

Then <em>L</em> - <em>R</em> = 1.

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3 years ago