The probability value become is 2c/(N-1).
According to the statement
we have given that If P and Q are both neighbors of R, and by considering unstructured network in which each node randomly chooses c neighbors.
we have to find that the probability of neighbors that they are also neighbors of each other.
So, For this purpose to find the probability is
Consider a network of N nodes unstructured and let
If each node chooses c neighbors at random,
then the probability that P will become by choose Q, or Q chooses P is roughly 2c/(N-1).
And the probability outcomes value become is 2c/(N-1).
So, The probability value become is 2c/(N-1).
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Log w (x^2-6)^4
Using log a b = log a + log b, with a=w and b=(x^-6)^4:
log w (x^2-6)^4 = log w + log (x^2-6)^4
Using in the second term log a^b = b log a, with a=x^2-6 and b=4
log w (x^2-6)^4 = log w + log (x^2-6)^4 = log w + 4 log (x^2-6)
Then, the answer is:
log w (x^2-6)^4 = log w + 4 log (x^2-6)
Answer:
1/3.
Step-by-step explanation:
Prob(Drawing white marble) = 2/3
Prob(Drawing a black marble on second draw ) = 1/2
So:
Prob(Drawing a white then a red marble) = 2/3 * 1/2
= 2/6
= 1/3.
Answer:
Your answer is: Use the percentage formula: P% * X = Y
Step-by-step explanation:
Hope this helped : )
Su respuesta es: Utilice la fórmula de porcentaje: P% * X = Y
Espero que esto haya ayudado :)
Answer:
4/6
Step-by-step explanation:
