11 protons, 12 neutrons, and 11 electrons. What is the atomic mass of the atom? * 1 point

1 answer:

6 0

It would be 11 + 12 = 23 atomic mass units.
(electrons have about a mass of 5.489×10−4 atomic mass units, so their mass would be negligible in this calculation).

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Solve for c solve for r

expeople1 [14]

Answer:

Step-by-step explanation:

9(c+7)=27

9c+63=27 subtract 63 from both sides

9c= -36 divide by 9

c= -4

3(2r-8)+4r=76 foil

6r-24+4r=76 combine like terms

10r-24=76 add 24 to both sides

10r+100 divide by 10

r= 10

7 0

3 years ago

Can someone help me with this truth table. I just don't understand how to do it.

RUDIKE [14]

An implication $(p\implies q)$ is true if either the premise $(p)$ is false, or both the premise and conclusion $(p\text{ and }q)$ are both true, and false otherwise.

$\begin{array}{c|c|c|c|c|c|c}p&q&p\implies q&\neg q&(p\implies q)\land\neg q&\neg p&(p\implies q)\land\neg q\implies\neg p\\T&T&T&&&&\\T&F&F&&&&\\F&T&T&&&&\\F&F&T&&&&\end{array}$

Negation $(\neg q)$ is straightforward; if a statement is true, then its negation is false, and vice versa.

$\begin{array}{c|c|c|c|c|c|c}p&q&p\implies q&\neg q&(p\implies q)\land\neg q&\neg p&(p\implies q)\land\neg q\implies\neg p\\T&T&T&F&&F\\T&F&F&T&&F\\F&T&T&F&&T\\F&F&T&T&&T\end{array}$

A conjunction $(p\land q)$ is true if both premises are true, and false otherwise.

$\begin{array}{c|c|c|c|c|c|c}p&q&p\implies q&\neg q&(p\implies q)\land\neg q&\neg p&(p\implies q)\land\neg q\implies\neg p\\T&T&T&F&F&F\\T&F&F&T&F&F\\F&T&T&F&F&T\\F&F&T&T&T&T\end{array}$

Finally, by the rules of implication, we can fill the last column:

$\begin{array}{c|c|c|c|c|c|c}p&q&p\implies q&\neg q&(p\implies q)\land\neg q&\neg p&(p\implies q)\land\neg q\implies\neg p\\T&T&T&F&F&F&T\\T&F&F&T&F&F&T\\F&T&T&F&F&T&T\\F&F&T&T&T&T&T\end{array}$