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inysia [295]
3 years ago
13

Help me please, I don't get it.

Mathematics
1 answer:
aniked [119]3 years ago
5 0

they say a = 32

 so replace 32 for a in the equation so a divided by4 becomes 32 divided by 4 which equals 8

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6th grade math, help pleasee:)
Kamila [148]

Answer: a) v=12 feet

b) 1: 12

2: 24

3: 36

4: 48

Step-by-step explanation:

A) v=d/t

They give you 60 feet, which can be plugged in for d (distance), and 5 seconds which can be plugged into t (time).

So, v=60/5=12

B) Kendall runs 12 feet per second, so in the chart:

1 sec x 12 feet = 12 feet

2 sec x 12 feet = 24 feet

3 sec x 12 feet = 36 feet

4 sec x 12 feet = 48 feet

7 0
3 years ago
Tyler has 120 linear feet of fencing to put around his garden. If he uses the fence to border a rectangular garden, what is the
Travka [436]

Answer:

The maximum area is 900\ ft^{2}

Step-by-step explanation:

Let

x----> the length of rectangle

y---> the width of rectangle

we know that

The perimeter of rectangle is equal to

P=2(x+y)

we have

P=120\ ft

so

120=2(x+y)

60=(x+y)

y=60-x------> equation A

Remember that

The area of rectangle is equal to

A=xy -----> equation B

substitute equation A in equation B

A=x(60-x)

A=-x^{2} +60x

This is a vertical parabola open downward

The vertex is a maximum

The y-coordinate of the vertex of the graph is the maximum area of the garden and the x-coordinate is the length for the maximum area

using a graphing tool

The vertex is the point (30,900)

see the attached figure

Find the value of y

y=60-x ----->  y=60-30=30\ ft

The dimensions of the rectangular garden is 30\ ft by 30\ ft

For a maximum area the garden is a square

The maximum area is 900\ ft^{2}

5 0
3 years ago
To the nearest cent what is $47.40 decreased by 58%
Rashid [163]
4700 is the answer hope it helps
3 0
3 years ago
Read 2 more answers
GIVING AWAY 15 POINTS. Graph A(-2, 5) and B (-3, 6). Then reflect A and B over the y-axis. What are the missing coordinates for
stira [4]
A' (2,5)
B' (3,6)


When reflecting over only y axis, flip the negative/positive sign for the x value
When reflecting over only x axis, flip the negative/poditive sign for the y value
3 0
3 years ago
A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu
telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 110, p = 0.2

So

\mu = E(X) = np = 110*0.2 = 22

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 22}{4.1952}

Z = 0.715

Z = 0.715 has a pvalue of 0.7626.

X = 17

Z = \frac{X - \mu}{\sigma}

Z = \frac{17 - 22}{4.1952}

Z = -1.19

Z = -1.19 has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

4 0
4 years ago
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