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3 years ago

-8.68 divided -0.024

Mathematics

2 answers:

Tanzania [10]3 years ago

5 0

Answer:

1085/3 = 361.7

Step-by-step explanation:

Expand −8.68/0.024 ≈361.666666667 by multiplying both numerator and the denominator by 1000.

8680/-24 ≈361.666666667

Reduce the fraction −8680/24≈361.666666667 to lowest terms by extracting and canceling out −8.

1085/3≈361.7

marishachu [46]3 years ago

3 0

Answer:

-8.704

Step-by-step explanation:

hav a great day

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JulijaS [17]

The answer is C 7v-1

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3 years ago

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A monkey is swinging from a tree. On the first swing, she passes through an arc whose length is 24 m 24 m24, start text, space,

Alchen [17]

Answer:

$24(\frac{1}{2})^{n-1}$

Step-by-step explanation:

Complete Question:

A monkey is swinging from a tree. On the first swing, she passes through an arc whose length is 24 m. With each swing, she travels along an arc that is half as long as the arc of the previous swing. Which expression gives the total length the monkey swings in her first n swings?

Solution:

First Swing:

24 m

Second Swing:

Half of first, so

24(1/2)

Third Swing:

Half of second, so:

24(1/2)(1/2)

Fourth Swing:

24(1/2)(1/2)(1/2)

So we see the general formula as:

$24(\frac{1}{2})^{n-1}$

Note: n -1 because (1/2) plays a role from second swing, which is n - 1

where n is the number of swings

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3 years ago

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3. A rare species of aquatic insect was discovered in the Amazon rainforest. To protect the species, environmentalists declared

navik [9.2K]

The number of months until the insect population reaches 40 thousand is 14.29 months and the limiting factor on the insect population as time progresses is 250 thousands.

Given that population P(t) (in thousands) of insects in t months after being transplanted is P(t)=(50(1+0.05t))/(2+0.01t).

(a) Firstly, we will find the number of months until the insect population reaches 40 thousand by equating the given population expression with 40, we get

P(t)=40

(50(1+0.05t))/(2+0.01t)=40

Cross multiply both sides, we get

50(1+0.05t)=40(2+0.01t)

Apply the distributive property a(b+c)=ab+ac, we get

50+2.5t=80+0.4t

Subtract 0.4t and 50 from both sides, we get

50+2.5t-0.4t-50=80+0.4t-0.4t-50

2.1t=30

Divide both sides with 2.1, we get

t=14.29 months

(b) Now, we will find the limiting factor on the insect population as time progresses by taking limit on both sides with t→∞, we get

$\begin{aligned}\lim_{t \rightarrow \infty}P(t)&=\lim_{t \rightarrow \infty}\frac{50(1+0.05t)}{2+0.01t}\\ &=\lim_{t \rightarrow \infty}\frac{50(\frac{1}{t}+0.05)}{\frac{2}{t}+0.01}\\ &=50\times \frac{0.05}{0.01}\\ &=250\end$

(c) Further, we will sketch the graph of the function using the window 0≤t≤700 and 0≤p(t)≤700 as shown in the figure.

Hence, when the population P(t) (in thousands) of insects in t months after being transplanted by P(t)=(50(1+0.05t))/(2+0.01t) then the number of months until the insect population reaches 40 thousand 14.29 months and the limiting factor on the insect population is 250 thousand and the graph is shown in the figure.

Learn more about limiting factor from here brainly.com/question/18415071.

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