Option C:
![\ln 64 y^{2}](https://tex.z-dn.net/?f=%5Cln%2064%20y%5E%7B2%7D)
Solution:
Given expression: 2 ln 8 + 2 ln y
Applying log rule
in the above expression.
⇒ ![2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}](https://tex.z-dn.net/?f=2%20%5Cln%208%2B2%20%5Cln%20y%3D%5Cln%208%5E%7B2%7D%2B%5Cln%20y%5E%7B2%7D)
Applying log rule
in the above expression.
⇒ ![\ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)](https://tex.z-dn.net/?f=%5Cln%208%5E%7B2%7D%2B%5Cln%20y%5E%7B2%7D%3D%5Cln%20%5Cleft%288%5E%7B2%7D%20y%5E%7B2%7D%5Cright%29)
We know that ![8^{2}=64](https://tex.z-dn.net/?f=8%5E%7B2%7D%3D64)
⇒
Hence, the expression in single natural logarithm is
.
Answer:
The second number in an ordered pie of numbers that corresponds to a point on a coordinate system is the y<u>-value.</u>
2/7 is the probability that the first satellite sends a weak signal. That leaves 6, one of which sends a weak signal. So the probability that the second also sends a weak signal is 1/6. Combine these and we get 2/7×1/6=1/21.
Hello! The answer to your question would be as followed:
<u><em>4.98 x 10^5 </em></u>