Question

I need help fast !!Please reply asap

Answer 1

Answer:

A

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

To calculate m use the slope formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with ( x₁, y₁ ) = (0, - 3) and (x₂, y₂ ) = (4, 0)

m = $\frac{0+3}{4-0}$ = $\frac{3}{4}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{4}{3}$

y = - $\frac{4}{3}$ x + c ← is the partial equation

To find c substitute (4, - 6) into the partial equation

- 6 = - $\frac{16}{3}$ + c ⇒ c = - 6 + $\frac{16}{3}$ = - $\frac{2}{3}$

y = - $\frac{4}{3}$ x - $\frac{2}{3}$ ← in slope- intercept form

Multiply all terms by 3

3y = - 4x - 2 ( add 4x to both sides )

4x + 3y = - 2 ← in standard form

Answer 2

Answer:

4x+3y= -2

Step-by-step explanation:

rise over run

right or up = positive

left or down = negitive

you go up 3

you go right 4

4-6= -2

4x+3y= -2