Little of, not in plethora, small numbered
Answer:
g(t) - h(t) = -2t - 1
Step-by-step explanation:
g(t) - h(t) = t-3-3t+2
= -2t -1
Using pythagorean identities,tan(sin^-1(-5/13))= tan(arcsin(-5/13))
Let A = arcsin(-5/13) = -arcsin(5/13)
Thus, sin A = -5/13 and cos A = sqrt(1 - (5/13)^2) = 12/13.= tan(A)= sin(A) / cos(A)= -5/13 / (12/13)= -5/12
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