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Neko [114]
3 years ago
15

A bag of sugar weighs 907.1 grams

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

A) .9071 kilograms

Step-by-step explanation:

there is 1000 grams per kg

there is 907.1 grams so thats less then a kg

so its A) .9071 kilograms

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Irina18 [472]

Answer:

A.

Step-by-step explanation:

8 0
3 years ago
Which special case is represented by x? - 121?
marissa [1.9K]

Answer:

A. the difference of two squares

Step-by-step explanation:

Please use the symbol " ^ " to indicate exponentiation.

Then we have x^2 - 11^2, which is the difference of two squares:

x^2 is a square, the square of x; and 11^2 is a square, the square of 11.

A. the difference of two squares

Note that a "difference of squares" is easily factored:

a² - b² = (a - b)(a + b)

and so your x² - 11² factors as follows:  (x - 11)(x + 11)

7 0
3 years ago
Read 2 more answers
Determine which relation is a function.
Nezavi [6.7K]
Functions can only have 1 value of 'x'.

Option A is not a function because it has two -5's

Option B is not a function because it has two -2's.

Option C is a function.

Option D is not a function because it has two 6's.
5 0
3 years ago
It is known that 50% of adult workers have a high school diploma. If a random sample of 8 adult workers is selected, what is the
son4ous [18]

Answer:

85.56% probability that less than 6 of them have a high school diploma

Step-by-step explanation:

For each adult, there are only two possible outcomes. Either they have a high school diploma, or they do not. The probability of an adult having a high school diploma is independent of other adults. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

50% of adult workers have a high school diploma.

This means that p = 0.5

If a random sample of 8 adult workers is selected, what is the probability that less than 6 of them have a high school diploma

This is P(X < 6) when n = 8.

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.5)^{0}.(0.5)^{8} = 0.0039

P(X = 1) = C_{8,1}.(0.5)^{1}.(0.5)^{7} = 0.0313

P(X = 2) = C_{8,2}.(0.5)^{2}.(0.5)^{6} = 0.1094

P(X = 3) = C_{8,3}.(0.5)^{3}.(0.5)^{5} = 0.2188

P(X = 4) = C_{8,4}.(0.5)^{4}.(0.5)^{4} = 0.2734

P(X = 5) = C_{8,5}.(0.5)^{5}.(0.5)^{3} = 0.2188

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.0039 + 0.0313 + 0.1094 + 0.2188 + 0.2734 + 0.2188 = 0.8556

85.56% probability that less than 6 of them have a high school diploma

7 0
3 years ago
Twenty different books are to be put on five book shelves, each of which holds at least twenty books.
olya-2409 [2.1K]

Answer:

(a) 10,626 different arrangements

(b) 95,367,431,640,625 different arrangements

(c) 2.5852017 × 10²² different arrangements

Step-by-step explanation:

(a) How many different arrangements are there if you only care about the number of books on the shelves (and not which book is where)?

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626 arrangements

(b) How many different arrangements are there if you care about which books are where, but the order of the books on the shelves doesn't matter?

Since the order of the books on the shelves does not matter,

The calculation is given as

5²⁰ = 95,367,431,640,625 arrangements

(c) How many different arrangements are there if the order on the shelves does matter?

Since order matters now

Step 1

We use the combination formula for this

C(n , r) = n + r - 1C r - 1

n = 20

r = 5

= 20 + 5 - 1 C 5-1

= 24C4

= 24!/4 ! × (24 - 4)

= 24!/4! × 20!

= 10,626

Step 2

We find the factorial of the number books

= 20!

= 2,432,902,008,176,640,000

Step 3

The different arrangements there are if the order on the shelves does matter is calculated

= 10,626 × 2,432,902,008,176,640,000

= 2.5852017 × 10²² different arrangements

8 0
3 years ago
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