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4 years ago

What is the value of x? Enter your answer in the box. x =

Mathematics

2 answers:

Juliette [100K]4 years ago

6 0

3x + 50 = 6x - 10

3x (-6x) + 50 (-50) = 6x (-6x) - 10 (-50)

-3x = -60

-3x/-3 = -60/-3

x = 20

hope this helps

Tresset [83]4 years ago

5 0

Step 1: 3x + 50 = 6x - 10

Step 2: 3x + 50 (+10) = 6x - 10 (+10)

Step 3: 3x + 60 = 6x

Step 4: 3x (- 3x) + 60 = 6x (- 3x)

Step 5: 60 = 3x

Step 6: 60 / 3x = 3x / 3x

ANSWER: x = 20

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2 years ago

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Step-by-step explanation:

Let The given numbers be x

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x : 18 = x² - 5

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3 years ago

<img src="https://tex.z-dn.net/?f=%20%7B2%7D%5E%7Bm%7D%20%20%3D%20n%20" id="TexFormula1" title=" {2}^{m} = n " alt=" {2}^{m} =

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Answer:

$\displaystyle n^3-\frac{1}{n^{2}}$

Step-by-step explanation:

<u>Exponents Properties</u>

We need to recall the following properties of exponents:

$(a^x)^y=(a^y)^x=a^{xy}$

$\displaystyle a^{-x}=\frac{1}{a^x}$

We are given the expression:

$2^m=n$

We need to express the following expression in terms of n.

$8^m-4^{-m}$

It's necessary to modify the expression to use the given equivalence.

Recall $8=2^3 \text{ and }4 = 2^2$ . Thus:

$(2^3)^m-(2^2)^{-m}$

Applying the property:

$(2^m)^3-(2^m)^{-2}$

Substituting the given expression:

$n^3-n^{-2}$

Or, equivalently:

$\mathbf{\displaystyle 8^m-4^{-m}= n^3-\frac{1}{n^{2}}}$

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