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nydimaria [60]
3 years ago
14

Solve 4 square root of 3 = 8cos

Mathematics
1 answer:
sukhopar [10]3 years ago
4 0

Therefore \theta = 30^\circ

Step-by-step explanation:

Given,

4\sqrt{3 } =8 cos \theta

\Leftrightarrow cos \theta =\frac{4\sqrt{3} }{8}

\Leftrightarrow cos \theta =\frac{\sqrt{3} }{2}

\Leftrightarrow cos \theta =cos 30^\circ

\Leftrightarrow  \theta = 30^\circ

Therefore \theta = 30^\circ

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What is the measure of
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I think that it is D or B from my side

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What is the length of CD in this diagram, ABC - EDC,
natima [27]

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<h2>4</h2>

Option A is the right option.

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∆ABC~∆EDC

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8 0
3 years ago
Read 2 more answers
A rectangular prism has a length of 12 feet, a width of 6 feet, and a height of 2 feet.
aliina [53]
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3 0
3 years ago
A rock is thrown upward from a bridge that is 57 feet above a road. The rock reaches its maximum height above the road 0.76 seco
bekas [8.4K]

answer:

f(t) = -9.9788169(t -0.76)^2 +57

Step-by-step explanation:

On this question we see that we are given two points on a certain graph that has a maximum point at 57 feet and in 0.76 seconds after it is thrown, we know can say this point is a turning point of a graph of the rock that is thrown as we are told that the function f determines the rocks height above the road (in feet) in terms of the  number of seconds t since the rock was thrown therefore this turning point coordinate can be written as (0.76, 57) as we are told the height represents y and x is represented by time in seconds. We are further given another point on the graph where the height is now 0 feet on the road then at this point its after 3.15 seconds in which the rock is thrown in therefore this coordinate is (3.15,0).

now we know if a rock is thrown it moves in a shape of a parabola which we see this equation is quadratic. Now we will use the turning point equation for a quadratic equation to get a equation for the height which the format is f(x)= a(x-p)^2 +q  , where (p,q) is the turning point. now we substitute the turning point

f(t) = a(t-0.76)^2 + 57, now we will substitute the other point on the graph or on the function that we found which is (3.15, 0) then solve for a.

0 = a(3.15 - 0.76)^2 + 57

-57 =a(2.39)^2  

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-57/5.7121 =a

-9.9788169 = a      then we substitute a to get the quadratic equation therefore f is

f(t) = -9.9788169(t-0.76)^2 +57

4 0
3 years ago
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