3 years ago

Solve 4 square root of 3 = 8cos

Mathematics

1 answer:

sukhopar [10]3 years ago

4 0

Therefore $\theta = 30^\circ$

Step-by-step explanation:

Given,

$4\sqrt{3 } =8 cos \theta$

$\Leftrightarrow cos \theta =\frac{4\sqrt{3} }{8}$

$\Leftrightarrow cos \theta =\frac{\sqrt{3} }{2}$

$\Leftrightarrow cos \theta =cos 30^\circ$

$\Leftrightarrow \theta = 30^\circ$

Therefore $\theta = 30^\circ$

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