Question

Solve 4 square root of 3 = 8cos

Answer 1

Therefore $\theta = 30^\circ$

Step-by-step explanation:

Given,

$4\sqrt{3 } =8 cos \theta$

$\Leftrightarrow cos \theta =\frac{4\sqrt{3} }{8}$

$\Leftrightarrow cos \theta =\frac{\sqrt{3} }{2}$

$\Leftrightarrow cos \theta =cos 30^\circ$

$\Leftrightarrow \theta = 30^\circ$

Therefore $\theta = 30^\circ$