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creativ13 [48]
3 years ago
13

Please help me graph this thank you

Mathematics
1 answer:
SashulF [63]3 years ago
4 0

Answer:

Hi there! Please give the full question! There are many different questions that could go along with this graph!

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Can someone please explain the Pythagorean theorem to me?
Leona [35]

Answer:

Pythagoras theorem is is a mathematical law that states that the sum of squares of the lengths of the two short sides of the right triangle is equal to the square of the length of the hypotenuse.

Step-by-step explanation:

The hypotenuse is the side opposite to the right angle and so the equation for finding the hypotenuse would be:

a^2+^b^2=c^2

7 0
3 years ago
A ladder is leaning against the side of a building. The bottom of the ladder makes an angle of 73 degrees with the ground and is
Darina [25.2K]

Answer:

3.08

Step-by-step explanation:

you are looking for the hypotenuse, and have adjacent. So, use COS.

cos(73)=0.9/x

simplified 0.9/cos(73)

calculate.

5 0
3 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
3 years ago
50 Points
Harlamova29_29 [7]
The answer is C because it moves 5 right and 10 up so it’s still positive on both 5 is x and 10 is y
4 0
3 years ago
Can someone please help me?
Nana76 [90]

Answer: -5 or -5/1

Step-by-step explanation: Rise over Run

5 0
3 years ago
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