Perimeter of a rectangle = 6x + 8
Solution:
Given area of a rectangle = 
Let us first factor the given polynomial.


Taking out common terms in the above expression
Taking out common term
in the above expression


Area of a rectangle = l × b
Therefore,
and 
Perimeter of a rectangle = 2(l + b)
![=2[(2x+1)+(x+3)]](https://tex.z-dn.net/?f=%3D2%5B%282x%2B1%29%2B%28x%2B3%29%5D)



The answer is same if you take <em>l</em> = x + 3 and <em>b</em> = 2x + 1.
Hence, perimeter of a rectangle = 6x + 8.
<em><u>Question:</u></em>
If (x + 2)/2 = y /5, then which of the following must be true?
x/2 = (y-2)/5
x/2 = (y-5)/5
(x+2)/5 = y/25
<em><u>Answer:</u></em>
<em><u>The true is:</u></em>

<em><u>Solution:</u></em>
Given that,

The above expression can be rewritten as:

Move the constant 1 from left side of equation to right side of equation

Simplify the right side of equation by making the denominator same

Thus
is true
Answer:
4x is the answer
Step-by-step explanation:
3x + x= 4x + x = 5x - x = 4x
Answer:
A and C
Step-by-step explanation:
Answer:
Step-by-step explanation:
1. Cos 52° = adj/hyp
Cos 52° = x/13
x = 13×cos 52°
x = 8.00
2. Sin70° = opp/hyp
Sin70° = 30/x
x sin70° = 30
x = 30/sin70°
x = 31.93
x ≈ 32
3. Tan∅ = opp/adj
Tan∅ = 45/51
Tan∅ = 0.8824
∅ = tan-¹(0.8824)
∅ = 41.42°
∅ ≈ 41°