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uranmaximum [27]
3 years ago
6

Write the product as a trinomial. (x + 2)(x + 3) a. x2 + 5 b. x2 + 5x + 6 c. x2 + 6x + 5 d. x2 + 6x + 6

Mathematics
2 answers:
Leni [432]3 years ago
7 0
Use: (a + b)(c + d) = ac + ad + bc + bd

(x+2)(x+3)=(x)(x)+(x)(3)+(2)(x)+(2)(3)=x² + 3x + 2x + 6 = x² + 5x + 6

Answer: b. x² + 5x + 6
tino4ka555 [31]3 years ago
5 0
The answer would be b

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3 years ago
Consider the following system of equations.
Dmitrij [34]

Answer:

C. When the equations -10x + 5y = -60 and -3x − 5y = -5 are added together, a third linear equation, -13x = -65, is formed, and it shares a common solution with the original equations.

Step-by-step explanation:

2x-y=12

-3x-5y=-5

multiply the first equation by -5

-10x +5y = -60

add the 2 equations together

-3x-5y=-5

-10x +5y = -60

-------------------------

-13x = -65

We use the addition property of equality which says adding the same thing to both sides, doesn't change the equation, so we will get the same answer as the original equation

6 0
3 years ago
14/15 divided by 7/5
Charra [1.4K]

9514 1404 393

Answer:

  2/3

Step-by-step explanation:

There are a couple of different ways that division of fractions can be done.

1) "invert and multiply"

  \dfrac{14}{15}\div\dfrac{7}{5}=\dfrac{14}{15}\times\dfrac{5}{7}\\\\=\dfrac{14}{7}\times\dfrac{5}{15}=\boxed{\dfrac{2}{3}}

__

2) use the numerators when the denominators are the same

  \dfrac{14}{15}\div\dfrac{7}{5}=\dfrac{14}{15}\div\dfrac{21}{15}\\\\=\dfrac{14}{21}=\boxed{\dfrac{2}{3}}

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Step-by-step explanation:

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Step-by-step explanation:

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