From the double-angle identity,

we can rewritte our given equation as:

By factoring 2cosx on the left hand side, we have

This equation has 2 solutions when

From equation (A), we obtain

and from equation (B), we have

On the other hand, we can find one more solution from the original equation by substituting x=0, that is,

then, x=0 is another solution. In summary, we have obtained the following solutions:

However, the intersection of the last set is empty. So the unique solution is x=0 as we can corroborate on the following picture:
Therefore, the solution set is: {0}
hey 1-6 =5 is this what you were looking for?
W+9 or 9+w would be the answer
Answer:
No we can consider A as single event. See the explanation below
Step-by-step explanation:
Let's define the event A as:
A=" Select a 4 from a standard deck of 52 cards"
We know that in a standard deck we have 4 different types of 4, spade, heart, diamond and club.
And by definition of simple event we need to have just one possible outcome in the experiment, and on this case we have 4 possible options for event A, so for this reason the event A can't be considered as simpl event.