1st Example: first term 5, and ratio r = 2
5 , 10 , 20 , 40 , 80, ...
2nd Example: first term 5, and ratio r = - 2
5 , - 10 , +20 , -40, +80, ....
seperable differential equations will have the form
what you do from here is isolate all the y terms on one side and all the X terms on the other
just divided G(y) to both sides and multiply dx to both sides
then integrate both sides
once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it
In your problem,
so all you need to integrate is
Here, the given equation is,
x^2+y^2+px+6y-3=0
By copairing it with x^2+y^2+2gx+2fy+c=0, we get,
2g=p or, g=p/2
2f=6 or, f=3
c=-3
now the radius is,
r^2=g^2+f^2-c
or, 4^2=(p/2)^2 +3^2 -(-3)
or, 16= p^2/4 +9+3
or, 16-9-3=p^2/4
or p^2/4=4
or, p^2=4×4
or p^2=4^2
or p=4
therefore the rewuired value of p is 4.
The third one it could be one.
No, less than half of the applicants got an interview. 1/2 of the applicants would be 24 that would need to be interviewed.
To calculate the percentage: 22/48 x 100. This gives you 45.8% got interviewed.
