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olchik [2.2K]
3 years ago
10

Quadrilateral W X Y Z is shown. Diagonals are drawn from point W to point Y and from point Z to point X and intersect at point C

. The lengths of W C and C Y are congruent. Which best explains if quadrilateral WXYZ can be a parallelogram? WXYZ is a parallelogram because diagonal XZ is bisected. WXYZ is not necessarily a parallelogram because it is unknown if CZ = CY. WXYZ is a parallelogram because ZC + CX = ZX. WXYZ is not necessarily a parallelogram because it is unknown if WC = CY.
Mathematics
2 answers:
podryga [215]3 years ago
7 0

Answer:

3 the answer is three on edgenuity

Step-by-step explanation

u    u

 w

kkurt [141]3 years ago
5 0

Answer:

A.  WXYZ is a parallelogram because diagonal XZ is bisected.

Step-by-step explanation:

A parallelogram is an example of quadrilaterals which has pairs of opposite sides parallel and equal.

In the given question;

WC ≅ CY

⇒ WY = WC + CY

Considering diagonal WY,

ΔWYZ ≅ ΔWYX (diagonal property of a parallelogram)

WY ⊥ XZ (diagonals of a parallelogram bisect each other)

Thus;

XC ≅ CZ

Therefore. WXYZ is a parallelogram.  

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Step-by-step explanation:

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Answer:

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SOMEONE PLZZZ HELP ME THIS IS DUE IN LIKE 5 MINS (I WILL MARK BRAINLIEST)
andrew-mc [135]

Answer:

1) x = 8

2) ∠RPS = 36°

Step-by-step explanation:

<u>GIVEN :-</u>

  • ∠QPS = 180°
  • ∠QPR = 7x + 88
  • ∠RPS = 3x + 12

<u>TO FIND :-</u>

  1. Value of x
  2. Measure of ∠RPS

<u>FACTS TO KNOW BEFORE SOLVING :-</u>

In a straight line , if there are two angles such that their sum is equal to straight angle (or 180° in other words) , then those angles are known as linear pair.

<u>PROCEDURE :-</u>

1)

Measure of ∠QPS = 180° and it comprises of ∠QPR & ∠RPS.

⇒ ∠QPR & ∠RPS are linear pair.

⇒ ∠QPR + ∠RPS = 180°

⇒ 7x + 88 + 3x + 12 = 180°

⇒ 10x + 100 = 180

⇒ 10x = 180 - 100 = 80

⇒ x = 80/10 = 8

2)

x = 8. So,

∠RPS = 3×8 + 12 = 24 + 12 = 36°

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Montano1993 [528]

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<em>y</em> = <em>x</em>² - 9<em>x</em>   →   d<em>y</em>/d<em>x</em> = 2<em>x</em> - 9

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Then use the point-slope formula to get the equation of the tangent line:

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The normal line is perpendicular to the tangent, so its slope is -1/(-1) = 1. It passes through the same point, so its equation is

<em>y</em> - (-20) = 1 (<em>x</em> - 4)

<em>y</em> + 20 = <em>x</em> - 4

<em>y</em> = <em>x</em> - 24

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