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antiseptic1488 [7]
3 years ago
9

Simplify the expression below. (6-3)(66)

Mathematics
1 answer:
irinina [24]3 years ago
6 0

Answer:

198

Step-by-step explanation:

(6-3) x 66 subtract

3x66 multiply

198

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Mai is putting money into a checking account.Let Y represent the total amount of money in the account (dollars)Let X represent t
iragen [17]

Answer:

The answer is $40.

Step-by-step explanation:

According to the equation given in the question, we can assume that 550 is constant and was there when Mai started saving into a checking account.

Then as x gets increased by 1 each week, the amount of change in the account per week is $40.

I hope this answer helps.

5 0
3 years ago
In △ABC, AD and BE are the angle bisectors of ∠A and ∠B and DE ║ AB . Find the length of DE if perimeter of ABDE is 30 cm and AB
-BARSIC- [3]

Answer:

DE = 6 cm

Step-by-step explanation:

Let DE = x cm.

Since DE is parallel to AB therefore by the alternate interior angles theorem, m∠BAD = m∠ADE and m∠ABE = m∠DEB ............(1)

As AD is an angle bisector of ∠A, therefore m∠EAD = m∠DAB ; Since BE is an angle bisector of ∠B ⇒ m∠ABE = m∠EBD.

Therefore, from (1) We get ,  m∠EAD = m∠ADE and m∠EBD = m∠BED.

So, the triangles ADE and EDB are then isosceles with AE = ED and ED = DB.

So AE = DE = DB = x, and since the perimeter of ABDE is 30 cm, then

12 + x + x + x = 30

⇒ 12 + 3x = 30

⇒ x = 6

Hence, the length of DE is 6 cm.


8 0
3 years ago
Read 2 more answers
Last question i have to solve!!!!​
kramer
The location of the point that is 3/4 the distance from

4 0
3 years ago
Which of the following could be used to calculate the area of a sector in the circle shown below
lara [203]

Answer:

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Step-by-step explanation:

Given:

Radius = r = 8 in

θ = 42°

To Find:

Area of Sector = ?

Solution:

We know that

\textrm{Area of Sector}=\pi (Radius)^{2}\times \frac{\theta}{360}

Substituting the given values in the formula we get

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Which is the required Answer.

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

8 0
3 years ago
120 tickets were sold in one hour and 50% were childrens tickets how many childrens tickets were sold?
Elanso [62]

Answer:

60

Step-by-step explanation:

because half of children is 50. 120÷50=60

7 0
3 years ago
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