Ask question

Ask question

All categories

3 years ago

6

I know this seems like simple stuff but I get an awnser that's not on multiple choice so heres the problem: Pineapple costs $1.2

0 for 4 oz. What is the price per ounce?

2 answers:

shutvik [7]3 years ago

4 0

It is $0.3 per ounce.

Vlad1618 [11]3 years ago

3 0

Do you will need to find the unit rate. To do this, divide 1.20 by 4 and you will get 0.30. The answer is $0.30

You might be interested in

You are given that cos(A)=−35, with A in Quadrant II, and cos(B)=817, with B in Quadrant I. Find cos(A−B). Give your answer as a

neonofarm [45]

cos (A - B) is 36/85

<h3>How to simply the identity</h3>

Expand cos(A - B) with the identity

You get, cos(A - B) = cos(A) cos(B) + sin(A) sin(B)

Since A is in quadrant II, so sin(A) > 0,

B is in quadrant I, so sin(B) > 0.

Using the Pythagorean identity, we get

cos²(A) + sin²(A) = 1

Make sin A the subject of formula

$sin(A)^{2}$ = ( $\sqrt{(1 - (-3/5}$ )²)

Find the square root of both sides, square root cancels square

$sin A$ = 4/5

Repeat the same for the second value

$sin A^{2} = \sqrt{(1- 8/17)^2}$

$sin A$ = 15/17

Substitute values into cos(A - B)

cos(A - B) = cos(A) cos(B) + sin(A) sin(B) = (-3/5) * 8/17 + 4/5 * 15/17

cos (A - B) = 36/85

Therefore, cos (A - B) is 36/85

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

3 0

2 years ago

Read 2 more answers

Classify the number as rational or irrational.

Ainat [17]

Answer:

A. Rational

B. Irrational

C. Rational

D. Rational

i'm 100% sure! just finished my quiz

<em>hope this helps </em>^.^ !!!!

5 0

4 years ago

estimate the number of first-year students at an assembly meeting. He surveys 60 students and finds that 24 of them are first-ye

bogdanovich [222]

Answer:

The values needed to calculate a confidence interval at the 95% confidence level are $z = 1.96, n = 60, \pi = \frac{24}{60} = 0.4$

The 95% confidence interval for the proportion of first-year students at an assembly meeting is (0.276, 0.524).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 60, \pi = \frac{24}{60} = 0.4$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The values needed to calculate a confidence interval at the 95% confidence level are $z = 1.96, n = 60, \pi = \frac{24}{60} = 0.4$

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.4*0.6}{60}} = 0.276$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.4*0.6}{60}} = 0.524$

The 95% confidence interval for the proportion of first-year students at an assembly meeting is (0.276, 0.524).

6 0

3 years ago

Solve 2cos x+2cos 2x=0 on the interval [0,2pi)

rjkz [21]

$2cosx+2cos2x=0 \\ -2sin^2x+2cos^2x+2cosx=0 \\ -2(1-cos^2x)+2cos^2x+2cosx=0 \\ -2+2cos^2x+2cos^2x+2cosx=0 \\ 4cos^2x+2cosx-2=0 \\ t=cos x \\ 4t^2+2t-2=0 \\ \Delta=4+32=36 \\ t_1= \frac{-2-6}{8}=-1 \\ t_2= \frac{-2+6}{8}= \frac{1}{2} \\ cos x=-1 \lor cos x= \frac{1}{2} \\ x=-\pi \lor x= \frac{5\pi}{3}$

6 0

3 years ago

Read 2 more answers

How would you solve 180=g/12

Viefleur [7K]

Answer:

g=2160

Step-by-step explanation:

multiply both sides by 12

180*12=2160

g=2160

8 0

3 years ago