C. Integrate is the answer PLZ MARK AS BRAINLIEST
Answer: ......wlc;)
Explanation: Any information or data sent to a computer for processing is considered input. Input or user input is sent to a computer using an input device. The picture is an illustration of the difference between input and output. The input example (top) shows data being sent from a keyboard to a computer
Answer:
Need more details properly.
Explanation:
Please share more details through w-h-a-t-s-a-p-p at "plus one six four six three five seven four five eight five" to get the solution to this problem.
Thanks!
Answer:
you can go to settings and try to fix it or contact the people of this website
Explanation:
Big-O notation is a way to describe a function that represents the n amount of times a program/function needs to be executed.
(I'm assuming that := is a typo and you mean just =, by the way)
In your case, you have two loops, nested within each other, and both loop to n (inclusive, meaning, that you loop for when i or j is equal to n), and both loops iterate by 1 each loop.
This means that both loops will therefore execute an n amount of times. Now, if the loops were NOT nested, our big-O would be O(2n), because 2 loops would run an n amount of times.
HOWEVER, since the j-loop is nested within i-loop, the j-loop executes every time the i-loop <span>ITERATES.
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As previously mentioned, for every i-loop, there would be an n amount of executions. So if the i-loop is called an n amount of times by the j loop (which executes n times), the big-O notation would be O(n*n), or O(n^2).
(tl;dr) In basic, it is O(n^2) because the loops are nested, meaning that the i-loop would be called n times, and for each iteration, it would call the j-loop n times, resulting in n*n runs.
A way to verify this is to write and test program the above. I sometimes find it easier to wrap my head around concepts after testing them myself.
