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OLEGan [10]
4 years ago
11

Please help asap 2 questions 55 pts

Mathematics
1 answer:
Artist 52 [7]4 years ago
5 0
2x-2 must be zero or greater, since we cannot have a negative quantity under the radical sign (unless we allow for imaginary roots).

Solving 2x-2≥0, we get x-1≥0, or x≥1.  x must be equal to or greater than 1.


16 - 16, so the answer to the 2nd problem is the fourth one:  x=4.
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By the definition of a rectangle, JML and KLM are right angles.

<h3>How to explain the information?</h3>

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