4 - 4y - y² = 0
-y² - 4y + 4 = 0
y = -(-4) ± √((-4)² - 4(4)(-1))
2(-1)
y = 4 ± √(16 + 16)
-2
y = 4 ± √(32)
-2
y = 4 ± 4√(2)
-2
y = 4 + 4√(2) or y = 4 - 4√(2)
-2 -2
y = -2 - 2√(2) or y = -2 + 2√(2)
The answer is C.
The resulting expression should be: 35x-35y+21
Answer:
(-1/3
)(1/4)=(-1/12)
Step-by-step explanation:
(-1/3
)(1/4)
For fraction multiplication, multiply the numerators and then multiply the denominators to get
(-1/3
)(1/4)=(-1/12)
This fraction cannot be reduced.
Therefore:
(-1/3
)(1/4)=(-1/12)
We want to expand (2x + y²)⁵.
From Pascal's Triangle (shown below), the coefficients of the expansion are
1,5,10,10,5,1.
n=0: 1
n=1: 1 1
n=2: 1 2 1
n=3: 1 3 3 1
n=4: 1 4 6 4 1
n=5: 1 5 10 10 5 1
Therefore the third term in the expansion is
10*(2x)³*(y²)² = 10*(8x³)*(y⁴) = 80x³y⁴
Alternatively, the third term is
₅C₃ (2x)³(y²)² = 10*(8x³)*(y⁴) = 80x³y⁴
Answer: 80x³y⁴
1). 1n+5-1
N=26
2). n2+n n2+n
n3+n2+n
