Answer: 
<u>Step-by-step explanation:</u>
![\text{Use the distance formula: }d_AB=\sqrt{(x_A-x_B)^2+(y_A-y_B)^2}\\where\ (X_A, y_A)=(-3, -2)\\and\ (x_B,y_B)=(4, -7)\\\\\\d_AB=\sqrt{(-3-4)^2+[-2-(-7)]^2}\\\\.\quad =\sqrt{(-7)^2+(5)^2}\\\\.\quad =\sqrt{49+25}\\\\.\quad =\boxed{\sqrt{74}}](https://tex.z-dn.net/?f=%5Ctext%7BUse%20the%20distance%20formula%3A%20%7Dd_AB%3D%5Csqrt%7B%28x_A-x_B%29%5E2%2B%28y_A-y_B%29%5E2%7D%5C%5Cwhere%5C%20%28X_A%2C%20y_A%29%3D%28-3%2C%20-2%29%5C%5Cand%5C%20%28x_B%2Cy_B%29%3D%284%2C%20-7%29%5C%5C%5C%5C%5C%5Cd_AB%3D%5Csqrt%7B%28-3-4%29%5E2%2B%5B-2-%28-7%29%5D%5E2%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Csqrt%7B%28-7%29%5E2%2B%285%29%5E2%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Csqrt%7B49%2B25%7D%5C%5C%5C%5C.%5Cquad%20%3D%5Cboxed%7B%5Csqrt%7B74%7D%7D)
Answer:
R = (3P-30)/8
Step-by-step explanation:
subtract 30 from each side to get:
P-30 = 
R
multiply each side by 
to get:
· P - 30 = R
R = (3P-30)/8
A² + b² = c²
Where a and b are the legs and c is the hypotenuse
So, plug in 10 for one of the legs and 24 for the other leg
c will be left blank because that is what you are trying to find, the hypotenuse
10² + 24² = c²
100 + 576 = c²
676 = c²
Take the square root of both sides of the equation to isolate c
√676 = √c²
Square of c and the square root cross out on the right
Take the square root of 676
c = 26
So, the length of the hypotenuse is 26 centimeters
The zeros of a function are the values of x that make the function be equal to zero.
When graphing a quadratic equation, the graph is a parabola, and the zeros of the function are the x-intercepts of the graph, which are the points where the graph intersects the x-axis.
So, if the zeros of this function are x = -8 and x = 2, that means the parabola crosses the x-axis at x = -8 and x = 2.
Therefore the correct option is the first one.
Answer:
A = 35 square units
Step-by-step explanation:
Formula to calculate the distance between two points 
and 
is,
d = 
Length of the segment between A(2, 2) and B(9, 2) = 
= 7 units
Length of the segment between B(9, 2) and C(9, -3) = 
= 5 units
Length of the segment between C(9, -3) and D(2, -3) = 
= 7 units
Length of the segment between A(2, 2) and D(2, -3) = 
= 5 units
Therefore, given polygon is a rectangle.
Area of the rectangle = length × width
= 7 × 5
= 35 square units
