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DedPeter [7]
3 years ago
10

Estimate how many times larger 4 x 1015 is than 19 x 1012.

Mathematics
2 answers:
Sveta_85 [38]3 years ago
7 0

<u>Answer:</u> The first number is 200 times greater than second number.

<u>Step-by-step explanation:</u>

Let the first number be 'x' and second number be 'y'

We are given:

x = 4\times 10^{15}

y = 19\times 10^{12}

To calculate the times, number 'x' is greater than number 'y', we divide the two numbers:

\frac{x}{y}=\frac{4\times 10^{15}}{19\times 10^{12}}\\\\\frac{x}{y}=0.2\times 10^3\\\\x=200y

Hence, the first number is 200 times greater than second number.

Paraphin [41]3 years ago
5 0
(4·10¹⁵)/(19·10¹²) ≈ (4/20)·10³ = 0.2·1000 = 200

The appropriate choice is ...
  D) 200 times larger
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Ellen plans to leave an 18 percent tip with her $23.75 lunch bill. Which of these expressions could she use to determine her tot
Makovka662 [10]

You probably forgot to mention the options. After a little research, I was able to get the complete question with the mentioned options you should have mentioned. The potential complete question is:

<em>Ellen plans to leave an 18 percent tip with her $23.75 lunch bill. Which of these expressions could she use to determine her total bill? </em>

<em>Check all that apply. </em>

<em>(1.18)(23.75) 23.75 – [(0.18)(23.75)] 23.75 + [(0.18)(23.75)] (0.18)(23.75)</em>

<em />

Answer:

The expression 23.75\:+\:\left[\left(0.18\right)\left(23.75\right)\right] will determine her total bill.

Step-by-step explanation:

Total lunch bill = $23.75

As he pans to 18% tip of the total bill, so the expression will be:

=23.75\:+\:\left(\:18\%\:\:of\:\:23.75\:\right)

=23.75\:+\:\left(\:\frac{18}{100}\:\times \:23.75\:\right)

=23.75\:+\:\left(\:0.18\times \:23.75\:\right)

or

=23.75\:+\:\left[\left(0.18\right)\left(23.75\right)\right]

Therefore, the expression 23.75\:+\:\left[\left(0.18\right)\left(23.75\right)\right] will determine her total bill.

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Step-by-step explanation:

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Answer:

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The amount of the coins in the coin bank = Php 1,570

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The number of Php 5 coins = The number of Php 1-coins + 14

Let 'x' represent the number of Php-5 coins, let 'y' represent the number of Php 10-coins, and let 'z' represent the number of Php 1-coins, we get;

x = 2 × y...(1)

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From equation (1) equation (2), and equation three, we have;

y = x/2

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