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Rasek [7]
3 years ago
8

A checkerboard measures 38.1 cm by 38.1 cm. What is the area of the checkerboard?

Mathematics
2 answers:
Lina20 [59]3 years ago
6 0
The answer might be1454.61
jeka943 years ago
3 0
You have to multiply 38.1 times 38.1 so it would be
 38.1*38.1 = 1451.61 square cm<span>
</span>
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Please help<br><br>numbers 42, 43, 44
Aleks [24]
<h3>Answer:</h3>

42.  29°

43.  3x³ +2x² -3x +10

44.  20a² +68a

<h3>Step-by-step explanation:</h3>

42.  The right-angle corner tells you the two marked angles are complementary — they sum to 90°.

  (-3x +20)° + (-2x +55)° = 90°

  -5x +75 = 90 . . . . . . . . . . collect terms, divide by °

  -5x = 15 . . . . . . . . . . . . . . . subtract 75

  x = -3 . . . . . divide by the coefficient of x

The angle of interest is (-3x+20)°. Filling in the found value for x, we have ...

  (-3·(-3) +20)° = 29° = m∠BDC

___

43.  The distributive property is useful for multiplying polynomials.

  (x +2)(3x² -4x +5) = x(3x² -4x +5) +2(3x² -4x +5)

  = 3x³ -4x² +5x +6x² -8x +10 . . . . . eliminate parentheses

  = 3x³ +2x² -3x +10

___

44.  Area is the product of length and width, so this becomes a problem in multiplying polynomials.

  area = (5a +17)(4a) = 20a² +68a . . . . area in square feet

3 0
3 years ago
How long will each person take to run a total of 50 miles at the given rates?
forsale [732]
Problema Solution

Terrance and Jesse are training for a long-distance race. Terrance trains at a rate of 6 miles every half hour, and Jesse trains at a rate of 2 miles every 15 minutes.

How long will each person take to run a total of 50 miles at the given rates?

Answer provided by our tutors

d = 50 mi the distance
t1 = the time of Terrance
t2 = the time of Jesse
Terrance trains at a rate of 6 miles every half hour thus his rate is:
v1 = 6/0.5 = 12 mph
Jesse trains at a rate of 2 miles every 15 minutes thus his rate is:
v2 = 2/(15/60) = 8 mph
since speed = distance/time follows time = distance/speed:
t1 = d/v1
t1 = 50/12
t1 = 4 1/6 hr
t1 = 4 hr 10 min
t2 = d/v2
t2 = 50/8
t2 = 6 1/4 hr
t2 = 6 hr 15 min
Terrance will run 4 hours and 10 minutes.
Jesse will run 6 hours and 15 minutes.

6 0
3 years ago
Three 24-hour clocks show the time to be 12 noon. One of the clocks is always correct one loses a minute every 24 hours and one
Ganezh [65]

There is one clock that shows the right time so we do not have to worry about the one which is always correct.

Talking about the second clock that loses a minutes in every 24 hours (or in a day), so after 60 days (since it has lost 60 minutes because it is losing 1 minute everyday) it will show 11:00 a.m when it is exactly the noon.

So this way, in total it will take 60\times 24=1440 days before it shows the correct noon.

Now, the third clock gains a minute every 24 hours (or in a day) , after 60 days (when it has gained 60 minutes or a complete hour) it will show 1:00 p.m when it is exactly the noon.

This way, it will take 60\times 24=1440 days (since it has gained a minute everyday) when it shows the correct noon.

Therefore, it will take 1440 days before all the three clocks show the correct time again.

5 0
4 years ago
Question 1<br> Let f(x) = 2x^2 - 3x - 4 and g(x) = x + 5. Find (fg)(x).
Scilla [17]

The function (fg)(x) is a composite function

The value of the function (fg)(x) is 2x^3 + 7x^2 - 19x - 20

<h3>How to determine the function (fg)(x)?</h3>

The functions are given as:

f(x) = 2x^2 - 3x - 4 and g(x) = x + 5.

To calculate (fg)(x), we make use of

(fg)(x) = f(x) * g(x)

So, we  have:

(fg)(x) = (2x^2 - 3x - 4) * (x + 5)

Expand

(fg)(x) = 2x^3 - 3x^2 - 4x + 10x^2 - 15x - 20

Collect like terms

(fg)(x) = 2x^3 - 3x^2 + 10x^2 - 4x - 15x - 20

Evaluate

(fg)(x) = 2x^3 + 7x^2 - 19x - 20

Hence, the function (fg)(x) is 2x^3 + 7x^2 - 19x - 20

Read more about composite function at:

brainly.com/question/10687170

7 0
3 years ago
D(1)=3 d(n) = d(n-1) - 14 what is the third term in the sequence
Aliun [14]
2nd term  =  3 - 14 = -11
3rd tern = -11-14 = -25 answer
6 0
3 years ago
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