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BabaBlast [244]
3 years ago
7

Suppose that

Mathematics
1 answer:
Nat2105 [25]3 years ago
8 0
15 inches of wire costs 0.75......0.75/15 = 0.05 per inch

for 11 inches......0.05 * 11 = $ 0.55 <===
You might be interested in
If a =6, what is the value of 2a(3b + 5c)?
leva [86]

Answer:

<h2>36b + 60c</h2>

Step-by-step explanation:

Put a = 6 to the expression 2a(3b + 5c):

(2)(6)(3b + 5c) = 12(3b + 5c)               <em>use the distributive property</em>

= (12)(3b) + (12)(5c) = 36b + 60c

7 0
3 years ago
If x varies directly with y and x=6 when y=8, find x when y=18.
andrey2020 [161]

Answer:

x = 13.5

Step-by-step explanation:

direct variation

y = kx

substitute x and y to find k

8 = k*6

divide by 6

8/6 =k

4/3 = k

y = 4/3 x

now put in y =18

18 = 4/3 x

 multiply by 3/4

18 * 3/4 = 3/4 * 4/3 x

54/4 = x

change to a decimal

13.5 =x


6 0
3 years ago
PLEASE HELP <br><br> y/7=x<br> what is y?
AlekseyPX

Answer:

You can't find y in this way

Step-by-step explanation:

You should know the value of x

But you can say

Y=7x

5 0
2 years ago
Last year Austin, Texas received 23.5 inches pf rainfall. This year Austin received 21.2 inches of rainfall. Find the percent of
Anna71 [15]
Percent decrease=decrease/original times 100
decrease=23.5-21.2=2.3
original=23.5

percent decrease=2.3/23.5 times 100=0.0978 times 100=9.8%

B is answer
7 0
3 years ago
Read 2 more answers
From a group of 7 men and 6 women, five persons are to be selected to form a committee so that at least 3 men are there in the c
Ivan

The total possibilities can be 756 ways.

<h3>What is combination?</h3>

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order. Combinations can be confused with permutations.

Given:

The number of ways in which we can select atleast 3 men in the committee are 756.

Number of men = 7

Number of women = 6

Number of people that should be selected in the committee = 5

Now,

N(M = 3) = 7C_3* 6C_2

=35*15

=525

N(M = 4) = 7C_4* 6C_1

=35*6

=210

N(M = 3) = 7C_5* 6C_0

=21*1

=21

So, total possibilities can be = 525 + 210 + 21 = 756 ways.

learn more about combination here:

brainly.com/question/28390900

#SPJ4

7 0
1 year ago
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