A company specializes in custom home resales in an exclusive subdivision. A random sample of nine custom homes currently listed
for sale provided the following information on size and price. Here, x denotes size, in hundreds of square feet, rounded to the nearest hundred, and y denotes price, in thousands of dollars, rounded to the nearest thousand. Use the information to complete parts (a) through (g). x 26 27 33 29 29 34 30 40 22
y 540 555 575 577 606 661 738 804 496
a. Find the regression equation for the data points.
b. Graph the regression equation and the data points.
c. Describe the apparent relationship between the two variables under consideration.
d. Interpret the slope of the regression line.
e. Identify the predictor and response variables.
f. Identify outliners and potential influential observations.
g. Predict the values of the response variable for the specified values of the predictor variable, and interpret your results.
y 540 555 575 577 606 661 738 804 496
a. Find the regression equation for the data points.
b. Graph the regression equation and the data points.
c. Describe the apparent relationship between the two variables under consideration.
d. Interpret the slope of the regression line.
e. Identify the predictor and response variables.
f. Identify outliners and potential influential observations.
g. Predict the values of the response variable for the specified values of the predictor variable, and interpret your results.
1 answer:
Answer:
Step-by-step explanation:
Given data of x and y are tabulated and slope and intercept found out
X Y
26 540
27 555
33 575
29 577
29 606
34 661
30 738
40 804
22 496
SLOPE 15.89351852
Intercept 140.0833333
a) Regression equation is
y =15.89x+140.08
b) Enclosed
c) POsitive linear relation
d) When x increses by 1 unit y increases by 15.89 units
e) predictor is x and response is y
f) No outliers.Potential are
26 540
27 555
33 575
29 577
g) whenever we have x value we substitute in regression equation and find y
g)
You might be interested in
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So
has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater
Your answer is: 63 is 90% of 70.
The work (if needed) is shown above :)
The work (if needed) is shown above :)