Answer: 9 1/16
nine and one sixteenth
Step-by-step explanation:
Substitute x = 3 and y = 4 into the equation:
3x + 1/4^y
= 3(3) + 1/4^(2)
Then solve using the order BEDMAS (brackets, exponenets, division, multiplication, addition, subtraction).
= 3(3) + 1/4^(2)
= 3(3) + 1/16
= 9 + 1/16
= 9 1/16
Answer:
-3·m^12·n^6
Step-by-step explanation:
We assume you intend ...
(-24·m^5·n^4)/(8·m^-7·n^-2)
= (-24/8)·m^(5-(-7))·n^(4-(-2))
= -3·m^12·n^6
_____
If you really intend what you have written, then it simplifies to ...
(-24·m^5·n^4/8)·m^-7·n^-2 . . . . . note that all factors involving m and n are in the numerator
= (-24/8)·m^(5-7)·n^(4-2) = -3n^2/m^2
ST=4
3x-8+x=2x
4x-8=2x
-8=-2x
4=x
Hope I’m not too late !
