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Setler79 [48]
3 years ago
9

Help me please 25 points

Mathematics
2 answers:
svetlana [45]3 years ago
7 0

Answer:

Each year the machinery loses a value of 4500.

Step-by-step explanation:

xenn [34]3 years ago
5 0

It’s D, each 2 years it goes down by roughly 10,000. But each year, it goes down roughly half which gives you 4,500

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If x-9 is a factor of x-5x-36 what is the other factor
dimaraw [331]
The other factor would be (x + 4). We can find this by using synthetic division. To do this, we must first find the divisor, which would be 9, if we let x - 9 equal to zero and solve for x. Then, for the dividend, we can use the coefficients and constant term values. 
<u>9</u>| 1  -5  -36
<u>         9  36</u>
     1  4  0
Therefore, the other expression (x + 9) would be (x + 4). Hope this helped!
4 0
4 years ago
Read 2 more answers
25. Which is an example of an operation?<br> A) 12<br> B) 6ab<br> C) +<br> D) y
nasty-shy [4]
Letter c is an operation.
Addition
8 0
4 years ago
Help me please. I will mark brainliest!
mel-nik [20]

Answer:

The answer is 6.5 hours.

Step-by-step explanation:

If you multiply the hours need to work during that week days(6) and the hours worked during the weekend(3.5) you get 33.5 hours worked over all. then, you subtract 40(the hours wanted) and 33.5(the hours worked normally) and you get 6.5.

4 0
3 years ago
Write an EQUATION for the nth term of each arithmetic sequence<br><br> -1,-0.5,0,0.5,...
kaheart [24]
Ninth term is 2.5

you are adding 0.5 each time

-1,-0.5,0,0.5,1,1.5,2,2.5
8 0
3 years ago
Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.
statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that p = \frac{231}{361} = 0.6399

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

E = -31*0.4095 + 21*0.5905 = -0.29

The expected value of the proposition is of -0.29.

3 0
3 years ago
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