Answer:
0.918 is the probability that the sample average sediment density is at most 3.00
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 2.80
Standard Deviation, σ = 0.85
Sample size,n = 35
We are given that the distribution of sediment density is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling:

P(sample average sediment density is at most 3.00)
Calculation the value from standard normal z table, we have,
0.918 is the probability that the sample average sediment density is at most 3.00
Answer:
1. adjacent
2. vertical
3. vertical
4. neither
5. adjacent
let me know if it's wrong
Step-by-step explanation:
Im not sure but
(sarah + tara)/2 = 8
(20 + tara)/2 = 8
20 + tara = 16
tara = 4hours ?? it doesn’t make logical sense but this is the only way i can think of
sorry if this wasn’t helpful ;-;
To find g(f(4)), work from the inside out.
f(4) is 4^2+3, or 16+3, or 19. Now, we must find g(19).
This is 19+5/19. This is already a mixed number, though if you want an improper fraction solution, we have:
361/19+5/19
Which simplifies to:
366/19
Therefore, 366/19 is the answer.