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4 years ago

How to solve equations

1 answer:

6 0

If its 5 or 10 you just move the decimal over by one like if it is 20 percent over 10 you would add the decimal and multiply it by the first number in the tens place but if its 5 then you half the discount by the total number

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- 3 + 3x = 2x – 13 I have to use more characters...

DENIUS [597]

- 3 + 3x = 2x – 13

Bring -3 to the right side of the equation by adding 3 to both sides

(- 3 + 3) + 3x = 2x – 13 + 3

0 + 3x = 2x - 10

3x = 2x - 10

Bring 2x to the other side by subtracting 2x to both sides

3x - 2x = 2x - 2x - 10

x = -10

Check:

-3 + 3(-10) = 2(-10) - 13

-3 + (-30) = -20 - 13

-33 = -33

Hope this helped!

~Just a girl in love with Shawn Mendes

6 0

3 years ago

What is the equation of this graphed line?

pantera1 [17]

Answer:

y = - $\frac{1}{3}$ x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 3) and (x₂, y₂ ) = (6, - 7)

m = $\frac{-7+3}{6+6}$ = $\frac{-4}{12}$ = - $\frac{1}{3}$

Note the line crosses the y- axis at (0, - 5) ⇒ c = - 5

y = - $\frac{1}{3}$ x - 5 ← equation of line

4 0

3 years ago

Allyson accidentally missed her turn on her way to visit her aunt. By the time she realized her mistake, she had been driving fo

olya-2409 [2.1K]

Answer:

can u convert this to miles?

Step-by-step explanation:

6 0

3 years ago

Suppose that the population mean for income is $50,000, while the population standard deviation is 25,000. If we select a random

Fudgin [204]

Answer:

Probability that the sample will have a mean that is greater than $52,000 is 0.0057.

Step-by-step explanation:

We are given that the population mean for income is $50,000, while the population standard deviation is 25,000.

We select a random sample of 1,000 people.

Let $\bar X$ = sample mean

The z-score probability distribution for sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = population mean = $50,000

$\sigma$ = population standard deviation = $25,000

n = sample of people = 1,000

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the sample will have a mean that is greater than $52,000 is given by = P( $\bar X$ > $52,000)

P( $\bar X$ > $52,000) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ > $\frac{52,000-50,000}{\frac{25,000}{\sqrt{1,000} } }$ ) = P(Z > 2.53) = 1 - P(Z $\leq$ 2.53)

= 1 - 0.9943 = 0.0057

Now, in the z table the P(Z $\leq$ x) or P(Z < x) is given. So, the above probability is calculated by looking at the value of x = 2.53 in the z table which has an area of 0.9943.

Therefore, probability that the sample will have a mean that is greater than $52,000 is 0.0057.

5 0

3 years ago

When determining how well an observed set of frequencies fits an expected set of frequencies, what is the test statistic

sergij07 [2.7K]

Answer: $\chi^2$ test statistic.

Step-by-step explanation:

The chi-square ( $\chi^2$ ) test is a non-parametric statistical test(also known as Goodness of fit test) which is used to determine if a distribution of observed frequencies differs from the expected frequencies.

Chi-square statistic uses either nominal (categorical) or ordinal level data.

Hence, When determining how well an observed set of frequencies fits an expected set of frequencies, the test statistic is $\chi^2$ test statistic.

6 0

3 years ago