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Aliun [14]
3 years ago
8

Raisins sell for 3.50 per pound and granola sells for 5.90 a pound. Terri bought some raisins and granola. The total weight was

2.1 pounds and the cost was 8.79.
A. 0.6 pounds of raisins, and 1.5 pounds of granola
B. 1.1 pounds of raisins , and 1 pound of granola
C. 1 pound of raisins, and 1.1 pounds of granola
D. 1.5 pounds of raisins, and 0.6 pounds of granola

PLEASE HELP QUICK
Mathematics
1 answer:
Ksju [112]3 years ago
3 0
The correct answer is D.
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Step-by-step explanation:

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Answer:

Part 1) a=-\frac{1}{4c^6}

Part 2) a=-\frac{1}{4c^{-6}}

Step-by-step explanation:

Part 1) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2}c^{-2} ----> equation B

substitute equation B in equation A

a=2(-\frac{1}{2}c^{-2})^{3}

Applying property of exponents

(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}

therefore

a=-\frac{1}{4c^6}

Part 2) we have

a=2b^{3} ----> equation A

b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2} ----> equation B

substitute equation B in equation A

a=2(-\frac{c^{2}}{2})^{3}

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(x^{m})^{n}=x^{m*n}

x^{-m} =\frac{1}{x^{m}}

a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})

simplify

a=-\frac{c^{6}}{4}

therefore

a=-\frac{1}{4c^{-6}}

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