Question

Enzo and Beatriz are playing games at their local arcade. Incredibly, Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of tickets. What is the minimum number of games that Enzo could have played?

Answer 1

Answer:

its 11

Step-by-step explanation:

Beatriz 11 x 5 =55

so Enzo 5x11=55

think about it as the left is the number of tickets per game and on the right how many games they played see ez.

Answer 2

Given :Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game.We need to find the minimum number of games that Enzo could have played to win the same number of tickets.

The  minimum number of games that Enzo could have played to win the same number of tickets Will be the least common multiple of 11 and 5.

The  factors of 11 and 5 are

11=11x1

5= 5x1

Least common multiply = 11x5=5.

 The minimum number of games that Enzo could have played to win the same number of tickets is 55.