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kramer
3 years ago
12

Consider a rectangle with width of x units and an area of 10 square units. The length 1 of the rectangle can be

Mathematics
2 answers:
slavikrds [6]3 years ago
6 0

Answer:It’s C

Step-by-step explanation:

:)

NeTakaya3 years ago
6 0

The question asks us to find the a graph which represents the width of the rectangle increasing by 1 unit while the area remains constant. The best graph to model this, would be answer choice C

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A 16 oz package of brown rice costs 79 cents and 32 oz package of white rice costs $3.99. Which package is a better deal
worty [1.4K]
First off,we can find out how much an oz cost for each package:

Package of brown rice:
0.79÷16
=$0.049375
≈$0.049

Package of white rice:
3.99÷32
=$0.1246875
≈$0.125

Price of brown rice:$0.049 < price of white rice:$0.125

Therefore,brown rice is a better deal as it is cheaper.

Hope it helps!
5 0
3 years ago
PLEASE HELP ASAPPP :)) IM GIVING BRAINLIEST + POINTS!!
taurus [48]

Answer:

volume of the square pyramid is:

V = s2h/3

where s=side length and h= height

for square pyramid A

h(a)= 8in and s(a)=12in

volume of square pyramid for A =

V(a)=s2(a) h(a)/3

V(a)=122 . 8/3 \implies⟹ 144 . 8/3 \implies⟹ 1152/3 \implies⟹ 384 in3

for square pyramid B

h(b)=24in and s(b)=36in

volume of square pyramid for B =

V(b)=s2(b) h(b)/3

V(b)=362 . 24/3 \implies⟹ 1296 . 24/3 \implies⟹ 31104/3 \implies⟹ 10368 in3

We want to know how many times the volume of pyramid B is bigger than pyramid A :

= V(b)/V(a)

=10368/384

= 27 times

Step-by-step explanation:

hope this helps if not let me know have a great day

8 0
2 years ago
Jana needs new school clothes. She decides to buy 4 shirts for 15$ each and 2 pairs of pants for 35$ each. if the sales tax is 8
bija089 [108]

Answer:

15$+35$+8.25$=58.25

so the total of bill for Jana's new clothes is 58.25

5 0
3 years ago
Algebra 1 CR-8
antiseptic1488 [7]

\mathrm{Domain\:of\:}\:x^2+2x-15\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Range\:of\:}x^2+2x-15:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:-16\:\\ \:\mathrm{Interval\:Notation:}&\:[-16,\:\infty \:)\end{bmatrix}

\mathrm{Axis\:interception\:points\:of}\:x^2+2x-15:\quad \mathrm{X\:Intercepts}:\:\left(3,\:0\right),\:\left(-5,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:-15\right)

\mathrm{Vertex\:of}\:x^2+2x-15:\quad \mathrm{Minimum}\space\left(-1,\:-16\right)

4 0
2 years ago
Please help me ASAP​
Serggg [28]

The class 4S because you divide each number by its mean mark and standard division and 4S is the highest.

5 0
2 years ago
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