If we plot that point we find ourselves in QIV. The distance along the x axis is 4, and the distance down from that point is -3. If we create a right triangle with that segment, that segment serves as the hypotenuse of the triangle. We need its measure. Using Pythagorean's theorem, 
and 
. We see that c = 5. We need now to find the secant of that right triangle. Secant if the co-identity of cosine which is side adjacent over hypotenuse. That means that secant is the hypotenuse over the side adjacent. So our secant theta = 5/4
A camera is placed in front of a hyperbolic mirror. The equation of the hyperbola that models the mirror is y^2/16-x^2/9=1 where
x and y are in inches the camera is pointed toward the vertex of the hyperbolic mirror and is positioned such that the lens is at the nearest focus to that vertex. The lens is_____ inch(es) from the mirror.
1 answer:
Answer:
The lens is 6 inches from the mirror
Step-by-step explanation:
We need to find the distance of the lens from the mirror, if the camera is pointed toward the vertex of the hyperbolic mirror and is positioned such that the lens is at the nearest focus to that vertex.
Given:
where a² = 16 and b² = 9
Then c² = a² + b²
c² = 16+9
c² = 25
c= √25 = 5
The hyperbola is centered at (0,0)
The vertex is at (0,a) = (0,4)
The foci is at (0,c) = (0,5)
The distance from vertex to focus is
d= c-a = 5-4 = 1 inches
Total distance from lens to mirror is sum of distance d and foci c:
5+1= 6 inches
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Answer:
Equation:
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Step-by-step explanation:
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Hope this helps :)